解析 neo4j JSON 响应

问题描述

我有 neo4j 响应对象（我给你提供了整个响应，所以我会做对）：

result = {
    "records": [
        {
            "keys": [
                "criteria.name"
            ],"length": 1,"_fields": [
                "Perspective"
            ],"_fieldLookup": {
                "criteria.name": 0
            }
        },{
            "keys": [
                "criteria.name"
            ],"_fields": [
                "3D"
            ],"_fields": [
                "2D"
            ],"_fieldLookup": {
                "criteria.name": 0
            }
        }
    ],"summary": {
        "query": {
            "text": "MATCH (criteria:TEST_01)\nRETURN criteria.name\nLIMIT 3","parameters": {}
        },"queryType": "r","counters": {
            "_stats": {
                "nodesCreated": 0,"nodesDeleted": 0,"relationshipsCreated": 0,"relationshipsDeleted": 0,"propertiesSet": 0,"labelsAdded": 0,"labelsRemoved": 0,"indexesAdded": 0,"indexesRemoved": 0,"constraintsAdded": 0,"constraintsRemoved": 0
            },"_systemUpdates": 0
        },"updateStatistics": {
            "_stats": {
                "nodesCreated": 0,"plan": false,"profile": false,"notifications": [],"server": {
            "address": "localhost:7687","version": "Neo4j/4.1.0","protocolVersion": 4.1
        },"resultConsumedAfter": {
            "low": 2,"high": 0
        },"resultAvailableAfter": {
            "low": 80,"database": {
            "name": "neo4j"
        }
    }
}

我只需要从中获取单个“_fields”，如下所示：

{"Perspective","3D","2D"}

我该怎么做？

我最终成功地使用此代码从任何确切记录中获取了值：

a = Object.values(result.records)
b = Object.values(a[0]._fields)
console.log(b);

但我不明白如何处理数组中的每个“a”元素并提取“_fields”。

解决方法

您可以使用 for ... of 循环遍历 records 中的所有对象！

const result = {
    "records": [
        {
            "keys": [
                "criteria.name"
            ],"length": 1,"_fields": [
                "Perspective"
            ],"_fieldLookup": {
                "criteria.name": 0
            }
        },{
            "keys": [
                "criteria.name"
            ],"_fields": [
                "3D"
            ],"_fields": [
                "2D"
            ],"_fieldLookup": {
                "criteria.name": 0
            }
        }
    ],"summary": {
        "query": {
            "text": "MATCH (criteria:TEST_01)\nRETURN criteria.name\nLIMIT 3","parameters": {}
        },"queryType": "r","counters": {
            "_stats": {
                "nodesCreated": 0,"nodesDeleted": 0,"relationshipsCreated": 0,"relationshipsDeleted": 0,"propertiesSet": 0,"labelsAdded": 0,"labelsRemoved": 0,"indexesAdded": 0,"indexesRemoved": 0,"constraintsAdded": 0,"constraintsRemoved": 0
            },"_systemUpdates": 0
        },"updateStatistics": {
            "_stats": {
                "nodesCreated": 0,"plan": false,"profile": false,"notifications": [],"server": {
            "address": "localhost:7687","version": "Neo4j/4.1.0","protocolVersion": 4.1
        },"resultConsumedAfter": {
            "low": 2,"high": 0
        },"resultAvailableAfter": {
            "low": 80,"database": {
            "name": "neo4j"
        }
    }
}

let option1 = [];
let option2 = [];

// For each object in result.records,for (let val of result.records) {
  // Put everything in val._fields into our result array.
  // ... spreads the array,so all elements are inserted
  // individually in case,in the future,// there are multiple items in _fields.
  option1.push(...val._fields);
  
  // For the object you provided,you could just do
  // val._fields[0]. However,option1 is more generalizable
  // in case there's ever more than one thing in _fields.
  option2.push(val._fields[0]);
}

console.log(option1);
console.log(option2);