如何通过 Linux 命令将修复消息解析为 JSON 格式

问题描述

我修复了需要转换为 JSON 格式的消息文件，如下所示。我如何使用 shell 脚本来转换这些？

来自：

arr.map(val=> val.src.split(",")).flat()

致：

05/03 11:23:19.123456 << 8=FIX.4.2^9=451^35=D^49=abc^56=bcd
05/03 11:23:19.123457 << 8=FIX.4.2^9=451^35=D^49=abc1^56=bcd1
05/03 11:23:19.123458 << 8=FIX.4.2^9=451^35=D^49=abc2^56=bcd2

解决方法

我认为在期望的输出中遗漏 9=451 是一个意外。

$ awk 'BEGIN{FS="\\^|[ <]+"}{printf "{\"time\":\"%s %s\"",$1,$2; for(i=3;i<=NF;i++){split($i,a,/=/);printf ",\"%s\":\"%s\"",a[1],a[2]}; printf "\n"}' fix  
{"time":"05/03 11:23:19.123456","8":"FIX.4.2","9":"451","35":"D","49":"abc","56":"bcd"
{"time":"05/03 11:23:19.123457","49":"abc1","56":"bcd1"
{"time":"05/03 11:23:19.123458","49":"abc2","56":"bcd2"

这里有注释来解释它是如何工作的：

# BEGIN rule(s)
BEGIN {
    FS = "\\^|[ <]+"     # define two field separators,^ and any number or consecutive spaces or left angle brackets
}

# Rule(s)
{
    printf "{\"time\":\"%s %s\"",$2  # printing the time (which we treat separately as it's internally "split" by a space.
    for (i = 3; i <= NF; i++) {           # the other fields we can iterate over,NF in awk is the 'number of fields'
            split($i,/=/)             # use the loop variable i to reference the fields,split them into an array on the '='
            printf ",a[2]    # print the array elements formatted,all on one line
    }
    printf "\n"                           # add a new line when we're done
}