问题描述
这是:
std::mutex mutex;
for () {
std::unique_lock<mutex> lock(mutex);
// do something
lock.unlock();
}
在for循环的每次迭代中释放和获取锁等价于这个吗?
std::mutex mutex;
for () {
std::unique_lock<mutex> lock(mutex);
// do something
}
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解决方法
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