使用 tidygraph

问题描述

你好,希望一切顺利。 我对我之前的问题进行了编辑,希望它能更清楚。

我创建了一个 igraph 对象,并希望多次运行相同的分析并在每次迭代中提取一些信息。

我无法分享全部数据,所以我只分享了一小部分。 df_edge 如下:

library(dplyr)
job_1 <-c(1,2,6,5,7,8,8)
job_2 <- c(2,4,3,1,5)
weight <- c(1,1)

df_edge <- tibble(job_1,job_2,weight)
df_edge %>% glimpse()

Rows: 14
Columns: 3
$ job_1  <dbl> 1,8
$ job_2  <dbl> 2,5
$ weight <dbl> 1,1

df_node 如下:

job_id <- c(1,8)
job_type <- c(1,1)

df_node <- tibble(job_id,job_type)
df_node %>% glimpse()

Rows: 8
Columns: 2
$ job_id   <dbl> 1,8
$ job_type <dbl> 1,1

创建 igraph 对象:

library(igraph)
library(tidygraph)

tp_network_subset <- graph.data.frame(df_edge,vertices = df_node,directed = F)

job_type 列中的 df_node 摘要

    df_node %>%
     count(job_type)
   
A tibble: 4 x 2
  job_type     n
     <dbl> <int>
1        0     2
2        1     4
3        2     1
4        3     1

我手动执行的操作如下:

### finding a job_id that belongs to job_type==1 category

    df_node %>% filter(job_type==1) %>%
    select(job_id) 

 A tibble: 4 x 1
  job_id
   <dbl>
1      1
2      6
3      7
4      8
# for instance,I picked one of them and it is job_id = 6
### using the job_id to create a subgraph by selecting order 1 neighbors of this job_id (6)

node_test <- make_ego_graph(tp_network_subset,order = 1,nodes="6")

### creating a dataframe of this subgrapgh where there is no isolated nodes

df_test <- as_tbl_graph(node_test[[1]]) %>% 
    activate(nodes) %>%
    filter(!node_is_isolated()) %>% 
    as_tibble()
df_test %>% glimpse()
Rows: 6
Columns: 2
$ name     <chr> "1","2","4","5","6","8"
$ job_type <dbl> 1,1

## subgraph size is 6 which will be an outcome of interest
### if the graph is zero length,I should stop here and pick another job_id that belongs to job_type==1 category

在这个例子中,not zero length 中的图形所以我继续next step

 ### calculating the measure of interest in respect to job_type==1 category
 
   df_test %>% 
    summarise(job_rate= (nrow(df_test %>% filter(job_type==1)))/(nrow(df_test %>% 
    filter(job_type %in% c(1,3)))))
# 0.6

if job_rate > 0.5 ,我想保留子图的 job_rate 类别的 job_type=4 和行(对应节点)。在这种情况下,job_rate was 0.6 所以我保留以下内容

 df_final <- as_tbl_graph(node_test[[1]]) %>% 
        activate(nodes) %>%
        filter(!node_is_isolated()) %>% 
        as_tibble() %>% filter(job_type==0)

# A tibble: 1 x 2
   name  job_type
    <chr>    <dbl>
1    4            0

但是,我需要分配它们对应的 job__rate 和一些 other related columns。所以,我最喜欢的结果是

    name  job_type    subgraph_origin_id      job_rate  subgraph_size  no_(job_type==0)_in_subgrapgh    no_(job_type==1)_in_subgrapgh   no_(job_type==2)_in_subgrapgh   no_(job_type==3)_in_subgrapgh                                                           
    <chr>    <dbl>
1    4         0             6                  0.6         6

因此,我需要执行此过程并为所有 job_type==1 节点创建子图。如果图形不是 zero length 及其 job_rate > 0.5,则提取 那个子图形 中的所有 对应节点以及 job_rate 和其他最喜欢的结果中显示的列。

解决方法

这对你有用吗?

aggregate

给出

dflst <- split(df_node,job_type)
tpe <- as.numeric(names(dflst))
out <- tibble()
for (i in seq_along(dflst)) {
  df <- dflst[[i]]
  node_test_lst <- make_ego_graph(tp_network_subset,order = 1,nodes = df$job_id)
  origin_id <- df$job_id
  jtpe <- tpe[i]
  for (j in seq_along(node_test_lst)) {
    node_test <- node_test_lst[[j]]
    df_test <- as_tbl_graph(node_test) %>%
      activate(nodes) %>%
      filter(!node_is_isolated()) %>%
      as_tibble()
    if (nrow(df_test %>% filter(job_type == 0)) > 0 & any(df_test$job_type %in% 1:3)) {
      job_rate <- with(df_test,sum(job_type == jtpe) / sum(job_type %in% 1:3))
      if (job_rate > 0.5) {
        df_final <- df_test %>%
          filter(job_type == 0) %>%
          mutate(
            subgraph_origin_id = origin_id[j],job_rate = job_rate,subgraph_size = nrow(df_test)
          ) %>%
          cbind(
            setNames(
              as.list(table(factor(df_test$job_type,levels = 0:3))),sprintf("no_(job_type==%s)_in_subgrapgh",0:3)
            )
          )
        out <- out %>% rbind(df_final)
      }
    }
  }
}