问题描述
- p004c01.txt
- p004c05.txt
- p006c01.txt
- p006c02.txt
- p007c01.txt
- p007c03.txt
- p007c04.txt
...
$cat p004c01.txt
#header
122.5 -0.256 547
123.6 NaN 325
$cat p004c05.txt
#header
122.1 2.054 247
122.2 -1.112 105
$cat p006c01.txt
#header
99 -0.200 333
121.4 -1.206 243
$cat p006c02.txt
#header
122.5 2.200 987
99 -1.335 556
$cat p004.txt
122 -0.256 547
122 2.054 247
122 -1.112 105
文件 2
$cat p006.txt
122.5 2.200 987
121.4 -1.206 243
99 -1.335 556
99 -0.200 333
p????cxx.txt
猫 p004* | sed '/#/d'|排序 -k 1n | sed '/NaN/d' |awk '{print substr($1,2,3),$2,$3,$4,$5}' > p004.txt
谁能帮我编写所有数据的简单脚本? 谢谢:)
解决方法
也许这对你有用:
for f in {001..999}; do tail -n +2 p"$f"c* > p"$f".txt; done 2>/dev/null