问题描述
下面是代码示例,这是一个很长的日志,但我刚刚粘贴了它的一个片段。 我需要提取模式之间的行 ---------------------------------- 并将每个信息存储在分别为每个单独的文本文件。
Like:
------------------
info1
------------------
info2
------------------
info3
------------------
输出:
fetch info1 and store it into file1.txt
fetch info2 and store it into file2.txt
fetch info3 and store it into file3.txt
And so on...
++++++++++++++++++++++++++++++++++++++++++++++++ +++++++++++++++++++++++++++++++++++++++++++++
**This is the text data :**
------------------------------------------------------------------------
revision88 106 | rohit | 2018-06-08 13:41:46 +0530 (Fri,08 Jun 2018) | 1 line
initial code import from FinanavialAnalytics branch
------------------------------------------------------------------------
revision88 99 | dhammdip.sawate | 2018-06-04 20:59:48 +0530 (Mon,04 Jun 2018) | 1 line
Added Little Bit Java Support.!
Index: resources.properties
===================================================================
--- resources.properties (revision 98)
+++ resources.properties (revision 99)
@@ -1,15 +1,15 @@
####################Elastsic Search#########################
ElasticclusterName=UProbe
-ElasticHost=192.168.0.91
+ElasticHost=192.168.0.73
ElasticPort=19300
-essqlURL=http://192.168.0.91:19200/_sql?sql=
+essqlURL=http://192.168.0.73:19200/_sql?sql=
resultsize =1024
@@ -72,45 +72,65 @@
secfile /home/sandeep/Desktop/LIC/Uprobe-LIC/Uprobe-Dev.seed
licfile /home/sandeep/Desktop/LIC/Uprobe-LIC/Uprobe-Dev.lic
------------------------------------------------------------------------
revision88 | sandeep.yadav | 2018-05-31 15:31:26 +0530 (Thu,31 May 2018) | 1 line
Acc_Ref Data front-end side functionality with validation done.
------------------------------------------------------------------------
解决方法
试试这个:
lg = open("log.txt")
fl = open("temp.txt",'w')
cnt = 0
for i in lg:
if i == "------------------------------------------------------------------------\n":
fl.close()
cnt += 1
fl = open("file{}.txt".format(str(cnt)),'w')
else:
fl.write(i)
fl.close()
lg.close()
这甚至可以在不使用正则表达式的情况下完成。
,我已经假设,主文本文件位于名为“text.txt”的同一目录中,并且您希望将这些文件保存在同一目录中。请根据您的需要更改文件路径。这应该适合您:
with open('./text.txt','r') as content:
paragraphs = list(filter(lambda x : x != '',content.read().split('------------------------------------------------------------------------')))
for index,para in enumerate(paragraphs):
filepath = './new_file' + str(index) + '.txt'
with open(filepath,'w') as file:
file.write(para)
,
如果日志文件不是太大(例如 1GB),您可以使用:
with open('log.log') as f:
content = f.read()
content = content.split('------------------------------------------------------------------------')
for idx,info in enumerate(content):
with open('info{}.txt'.format(idx + 1),'w') as f:
f.write(info)
,
我认为“========...”也是其中一种模式,因此我使用了 re 模块...因此,如果需要,您可以添加更多模式 [原来有re.compile("-+|=+")]
import re
with open("file.txt","r") as input_file:
text = input_file.read()
regex = re.compile("-+")
mo = regex.findall(text)
text = text.split("\n")
mo_wanted_patterns = [pattern for pattern in mo if len(pattern) > 5]
print(mo_wanted_patterns)
output_text = []
for index,line in enumerate(text):
if line in mo_wanted_patterns:
filepath = 'new_file' + str(index) + '.txt'
with open(filepath,'w') as file:
file.write("\n".join(output_text))
output_text = []
elif line not in mo_wanted_patterns:
output_text.append(line)
编辑:我注意到它比其他人提供的代码复杂得多。实施正则表达式使事情变得更加复杂,但很想知道它是否适合您