你如何在python中检测png中某些像素的rgb值？

问题描述

我的代码截取了屏幕截图，（应该）测试屏幕截图中的任何像素是否是一般的 rgb 值（在我的示例中，它们的范围是：r_min、r_max 和 g_min、g_max。此外，end_time 是在那里确保有足够的时间扫描所有像素，因为它随后会截取另一张照片，并检查另一张照片中的像素，直到找到特定像素，然后更改变量（ fish_found) 从 0 到 1，并通过 if 语句。

这是我想出的代码：

    fish_found = 0
    im = screenshot('check.png')
    def find_fish(image_name):

        r_min = 140
        r_max = 190
        g_min = 85
        g_max = 185
        fish_found = 0
        img = Image.open(image_name)
        rgb = img.convert('RGB')
        for x in range(img.size[0]):
            for y in range(img.size[1]):
                r,g,b = rgb.getpixel((x,y))
                if r >= r_min and r <= r_max and g >= g_min and g <= g_max:
                    fish_found = fish_found + 1

    while True:
        im = screenshot('check.png',region=(990,415,20,20))
        end_time = datetime.Now() + timedelta(seconds=0.5)
        while datetime.Now() < end_time:
            find_fish('check.png')
        print(fish_found)
        if fish_found > 0:
            print("You found a fish")

解决方法

好的，为任何需要它的人更新：整个代码一团糟，我找到了一个更好的方法来确定像素是否匹配：

def function():
    pic = screenshot('screen.png',region=(985,420,30,30))
    width,height = pic.size

    for x in range(0,width,2):
        #modify the last digit to take greater steps,if you don't want to check every 
        #pixel
        for y in range(0,height,2):
            #same thing,change the 2 to any value you want

            r,g,b = pic.getpixel((x,y))
            #this gets the actual rgb value of the pixel

            if r in range(250,256) and g in range(195,215) and b in range(28,38):
                #put the range of values of r g b up here ^
                #down here you place your code (after you find out if they match,what do 
                #you do should be right here.
#after all of that,just call your function when you want to.
function()