将多行卷成具有相同列数和不同值的单行

问题描述

我有一个 ID 列，其中包含针对特定属性的不同值。 我希望将 4 行转换为 1 行。有多条记录

UNIQID    | NAME | AGE | SOURCE 
123       | John | 25  | StoreA
928       | John | 25  | StoreB
456       | John | 25  | StoreC
528       | John | 25  | StoreD

我需要如下输出 -

UNIQID_A    | UNIQID_B | UNIQID_C | UNIQID_D | NAME | AGE 
123         | 928      | 456      | 528      | John | 25  

我设法通过使用 sql 查询达到以下结果，但我不确定如何将这些值汇总为 1

SELECT  CASE WHEN Source = 'StoreA' THEN UNIQID END AS UNIQID_A,CASE WHEN Source = 'StoreB' THEN UNIQID END AS UNIQID_B,CASE WHEN Source = 'StoreC' THEN UNIQID END AS UNIQID_C,CASE WHEN Source = 'StoreD' THEN UNIQID END AS UNIQID_D,ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY AGE) AS ROWNO,* 
FROM Table

上述查询的输出为

UNIQID_A     | UNIQID_B | UNIQID_C | UNIQID_D | NAME | AGE | ROWNO
123          | NULL     | NULL     | NULL     | John | 25  | 1
NULL         | 928      | NULL     | NULL     | John | 25  | 2
NULL         | NULL     | 456      | NULL     | John | 25  | 3
NULL         | NULL     | NULL     | 528      | John | 25  | 4

感谢您的帮助。

解决方法

您可以在条件语句中使用 ^\d+[^-]+-\s+(?P<person>[^:]+):\s+(?P<text>.+) 聚合为一行，并按剩余的列分组

max

,

SELECT SUM(UNIQID_A) UNIQID_A,SUM(UNIQID_B) UNIQID_B,SUM(UNIQID_C) UNIQID_C,SUM(UNIQID_D) UNIQID_D,NAME,AGE FROM (
    SELECT CASE WHEN Source = 'StoreA' THEN UNIQID END AS UNIQID_A,CASE WHEN Source = 'StoreB' THEN UNIQID END AS UNIQID_B,CASE WHEN Source = 'StoreC' THEN UNIQID END AS UNIQID_C,CASE WHEN Source = 'StoreD' THEN UNIQID END AS UNIQID_D,AGE
    FROM Table) AS A 
GROUP BY NAME,AGE