问题描述
#include<iostream>
#include<queue>
#include<string> // probally not needed
#include<cctype>
using namespace std;
int main()
{
queue <string> str; // i created some kind of vector queue
cout << "Please enter a string." << endl;
string temp;
cin >> temp; // grabs the string
if(temp != "") // checks if string is empty
{
str.push(temp); // pushes it onto queue
for(int i = 0; i < temp.size(); i++) // suppose to go through
//each element in queue
{
//str.pop(temp); /pops an element as requied by assignment
toupper(i); // suppose to turn each letter upper case
}
}
else
{
exit(0); // exits the program if string is empty
}
cout << temp; // suppose to display queue,that should be in
//upper case form.
return 0;
}
我对编程还是很陌生，我不知道将队列实现为字符串。问题是 for 循环没有遍历每个字母，因此 (toupper()) 不能将它们大写。
提示：“编写一个程序，从用户那里获取一个句子（字符串）并将其放入一个字符队列中。然后程序应该将每个字符出列，将其转换为大写并将结果存储为一个句子（字符串） . 打印此过程的结果”。
解决方法
您可以通过以下方式执行此操作。
#include<iostream>
#include<queue>
#include<string> // probally not needed
#include<cctype>
using namespace std;
int main()
{
queue <char> str; //make it char queue
cout << "Please enter a string." << endl;
string temp,result = "";
getline (cin,temp); //grabs string,including spaces
if(temp != "") // checks if string is empty
{
// push each character into queue
for(int i = 0; i < temp.size(); i++) // suppose to go through
{
str.push(temp[i]);
}
while(!str.empty()) //take a char from queue and do the task pop them.
{
char tm = str.front();
str.pop();
tm = tm-32; // making lower to upper
result = result+tm;
}
}
else
{
exit(0); // exits the program if string is empty
}
cout << result; // suppose to display queue,that should be in
//upper case form.
return 0;
}