问题描述
我必须使用 AWS DMS 迁移表。在加载时，我必须修剪源表中的列并将其加载到目标。我在 AWS DMS 中找不到任何修剪转换规则。如何实现？
解决方法
您可以执行 public class Ai {
public static final Ai ai = new Ai();
private static int maxY = 8;
private static int maxX = 7;
private static int minY = 1;
private static int minX = 0;
private static ArrayList<Entity> whiteFigures;
private static ArrayList<Entity> blackFigures;
private static ArrayList<Move> moves;
public void processMoves() {
moves = new ArrayList<Move>();
resetLists();
for (Entity e : blackFigures) {
moves.addAll(calcMoves(e.getFigure(),blackFigures,whiteFigures));
}
System.out.println(moves.size());
//removeCheckMoves();
System.out.println(moves.size());
executeMove(moves.get((int) (Math.random() * moves.size())));
resetLists();
Schach.turn = true;
}
private void removeCheckMoves() {
Figure king = null;
for (Entity e : blackFigures) {
if (e.getFigure().type == Figure.king) {
king = e.getFigure();
break;
}
}
ArrayList<Move> legalMoves = new ArrayList<Move>();
for (Move m : moves) {
resetLists();
executeMove(m);
if(!isLegal(king)) {
legalMoves.add(m);
}
}
moves = legalMoves;
}
private boolean isLegal(Figure king) {
boolean check = false;
for (Entity w : whiteFigures) {
for (Move move : Utils.calcMoves(w.getFigure(),whiteFigures,blackFigures)) {
if (Utils.numToPos(move.to).x == king.x && Utils.numToPos(move.to).y == king.y) {
check = true;
break;
}
}
if(check) break;
}
return check;
}
private void executeMove(Move m) {
for (Entity e : blackFigures) {
if (e.getFigure().x == Utils.numToPos(m.from).x && e.getFigure().y == Utils.numToPos(m.from).y) {
e.getFigure().x = Utils.numToPos(m.to).x;
e.getFigure().y = Utils.numToPos(m.to).y;
e.gotoSquare(Utils.posToNum(e.getFigure()) - 8);
for (Entity w : whiteFigures) {
if (w.getFigure().x == e.getFigure().x && w.getFigure().y == e.getFigure().y) {
whiteFigures.remove(w);
break;
}
}
break;
}
}
}
private void resetLists() {
whiteFigures = new ArrayList<Entity>();
whiteFigures.clear();
whiteFigures.addAll(Schach.whiteFigures);
blackFigures = new ArrayList<Entity>();
blackFigures.clear();
blackFigures.addAll(Schach.blackFigures);
}
//calcMoves function (works fine no reference here for sure)
}
和 remove-prefix 作为修剪数据的方法吗？ Guide on how to do that here.
或者，您可以在每次向目标位置添加新数据时触发 Lambda 进行修剪。