问题描述
我正在尝试将满足特定条件的 csv 文件中的 surp 值减去另一个满足另一个条件的 surp 值,我必须重复 60 次,如下所示:
surp [prime type == 'nl_unamb' or 'nl_amb',target nr == '0',prime nr == '0'] 的值 - surp [prime type == 'en_unamb' or 'en_amb',target nr = '0',prime nr = '0'] 的值 = 值 1
...
surp [prime type == 'nl_unamb' or 'nl_amb',target nr == '59',prime nr == '59'] 的值 - surp [prime type == 'en_unamb' or 'en_amb',target nr = '59',prime nr = '59'] 的值 = 值 60
为此,我尝试了以下代码:
import pandas as pd
df = pd.read_csv("surprisal.primed_extracted.csv")
for i in range(60):
pr_nl = df.loc[(df['surp'])
& (df['prime_type'] == 'nl_unamb')
& (df['prime_type'] == 'nl_amb')
& (df['target_nr'] == i)
& (df['prime_nr'] == i)]
pr_en = df.loc[(df['surp'])
& (df['prime_type'] == 'en_unamb')
& (df['prime_type'] == 'en_amb')
& (df['target_nr'] == i)
& (df['prime_nr'] == i)]
df.['sub_prime_language'] = pr_nl.loc['surp'] - pr_en.loc['surp']
但是,我收到以下错误:
Traceback (most recent call last):
File "calculate.py",line 13,in <module>
& (df['prime_nr'] == i)]
File "/usr/lib/python2.7/dist-packages/pandas/core/ops.py",line 786,in wrapper
return filler(self._constructor(na_op(self.values,other.values),File "/usr/lib/python2.7/dist-packages/pandas/core/ops.py",line 758,in na_op
result = lib.vec_binop(x,y,op)
File "pandas/lib.pyx",line 914,in pandas.lib.vec_binop (pandas/lib.c:16248)
File "pandas/lib.pyx",line 907,in pandas.lib.vec_binop (pandas/lib.c:16122)
TypeError: unsupported operand type(s) for &: 'float' and 'bool'
我期待听到任何人能提出的任何解决方案!
亲切的问候,
米津
解决方法
暂无找到可以解决该程序问题的有效方法,小编努力寻找整理中!
如果你已经找到好的解决方法,欢迎将解决方案带上本链接一起发送给小编。
小编邮箱:dio#foxmail.com (将#修改为@)