Python 绘制 3D 直方图六边形

问题描述

我正在测试 broadcom 的 TOF 相机。它具有六边形像素。

我希望在 3D 中表示直方图，就像在构造函数中一样。

我测试了 vedo 库。但我无法给出 Z 中的值并对单元格重新排序并追踪到地面

   from vedo import *
   from vedo.pyplot import histogram
   import numpy as np

   N = 2000
   x = np.random.randn(N) * 1.0
   y = np.random.randn(N) * 1.5
   # hexagonal binned histogram:
   histo = histogram(x,y,bins=100,mode='hexbin',xtitle="\sigma_x =1.0",ytitle="\sigma_y =1.5",ztitle="counts",fill=True,cmap='terrain',)
   # add a formula:
   f = r'f(x,y)=A \exp \left(-\left(\frac{\left(x-x_{o}\right)^{2}}'
   f+= r'{2 \sigma_{x}^{2}}+\frac{\left(y-y_{o}\right)^{2}}'
   f+= r'{2 \sigma_{y}^{2}}\right)\right)'
   formula = Latex(f,c='k',s=1.5).rotateX(90).rotateZ(90).pos(1.5,-2,1)

   show(histo,formula,axes=1,viewup='z')

解决方法

您可以轻松地创建它，例如

from vedo import *
import numpy as np

settings.defaultFont = "Theemim"

vals = np.abs(np.random.randn(8*4)) # heights
cols = colorMap(vals,"RdYlBu")

items = []
k = 0
for i in range(8):
    for j in range(4):
        val = vals[k]
        col = cols[k]
        x,y,z = [i+j%2/2,j-j%2/6,val+0.01]
        hexa = Circle([x,y],r=0.55,res=6)
        hbar = hexa.extrude(val) # create the hex bar
        hbar.lighting("default").flat().c(col)
        txt = Text3D(precision(val,3),[x,z],s=.12,justify='center',c='k')
        items += [hbar,txt]
        k += 1

show(items,axes=dict(xtitle="x-cell"))

histogram plot3d python