我如何允许任何不是字母表的字符在java中保持原样

编程问答 2022-04-29

问题描述

我用 java 编写了这个程序，当用户输入字母格式的文本时，它会将其转换为数字格式，但是我如何以一种方式对程序进行编码，即当用户输入字母以外的其他内容时，它会保持原样.例如，如果用户输入“get.food”，输出将是“438.3663”，“get”后面的点保持原样。但是在我的程序中发生的情况是，如果用户输入“get.food”，输出将是“4383663”，它会在 get 之后删除点。我不明白为什么？

这是我的代码。提前致谢

导入 java.util.Scanner;

 public class Transalate  {
     
  public static void main(String[] args) {
      
      String alphaNumber;
      
      String translation="";

    Scanner kb = new Scanner(System.in);

    System.out.println("Please Enter an Alphabet to be Translated ");

    alphaNumber = kb.next();

    alphaNumber = alphaNumber.toUpperCase();

       while(!alphaNumber.equals("STOP")){
        for(int i=0; i<alphaNumber.length();i++)
        {
            if(alphaNumber.charAt(i)=='A')
                translation=translation+"2";
                else if(alphaNumber.charAt(i)=='B')
                translation = translation+"2";
                else if(alphaNumber.charAt(i)=='C')
                translation = translation+"2";
                else if(alphaNumber.charAt(i)=='D')
                translation = translation+"3";
                else if(alphaNumber.charAt(i)=='E')
                translation = translation+"3";
                else if(alphaNumber.charAt(i)=='F')
                translation = translation+"3";
                else if(alphaNumber.charAt(i)=='G')
                translation = translation+"4";
                else if(alphaNumber.charAt(i)=='H')
                translation = translation+"4";
                else if(alphaNumber.charAt(i)=='I')
                translation = translation+"4";
                else if(alphaNumber.charAt(i)=='J')
               translation = translation+"5";
                else if(alphaNumber.charAt(i)=='K')
                translation = translation+"5";
                else if(alphaNumber.charAt(i)=='L')
                translation = translation+"5";
                else if(alphaNumber.charAt(i)=='M')
                translation = translation+"6";
                else if(alphaNumber.charAt(i)=='N')
                translation = translation+"6";
                else if(alphaNumber.charAt(i)=='O')
                translation = translation+"6";
                else if(alphaNumber.charAt(i)=='P')
                translation = translation+"7";
                else if(alphaNumber.charAt(i)=='Q')
                translation = translation+"7";
                else if(alphaNumber.charAt(i)=='R')
                translation = translation+"7";
                else if(alphaNumber.charAt(i)=='S')
                translation = translation+"7";
                else if(alphaNumber.charAt(i)=='T')
                translation = translation+"8";
                else if(alphaNumber.charAt(i)=='U')
                translation = translation+"8";
                else if(alphaNumber.charAt(i)=='V')
                translation = translation+"8";
                else if(alphaNumber.charAt(i)=='W')
                translation = translation+"9";
                else if(alphaNumber.charAt(i)=='X')
                translation = translation+"9";
                else if(alphaNumber.charAt(i)=='Y')
                translation = translation+"9";
                else if(alphaNumber.charAt(i)=='Z')
                translation = translation+"9";
               
            }
            System.out.println(translation);
            
            translation="";
         
         
        
        System.out.println("Enter Another Alphabet Or Enter Stop to End");
         alphaNumber = kb.next();

        alphaNumber = alphaNumber.toUpperCase();
    }
        System.out.println("The End");

  }
}

解决方法

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alphanumericjavajavalettertranslation