问题描述
我有一些包含 time
列的表格
id | time
----|-------------------
1 | 2021-2-2 10:21:00
2 | 2021-2-2 10:24:00
3 | 2021-2-2 10:27:00
4 | 2021-2-2 10:29:00
id | time | diff | status
----|----------------------------------
1 | 2021-2-2 10:21:00 | None | None
2 | 2021-2-2 10:24:00 | 3:00 | 1
3 | 2021-2-2 10:26:00 | 2:00 | 0
4 | 2021-2-2 10:29:00 | 3:00 | 1
status = if diff >= 3 then 1 else 0
我该怎么做。我必须得到过去 7 天的数据,然后才能得到这张决赛桌。
解决方法
使用LAG
:
SELECT id,time,EXTRACT(EPOCH FROM time - LAG(time) OVER (ORDER BY time)) / 60 AS diff,(EXTRACT(EPOCH FROM time - LAG(time) OVER (ORDER BY time)) / 60 >= 3)::int AS status
FROM yourTable
ORDER BY time;