问题描述
我对 C++ 非常陌生,并决定从基于文本的基本 RPG 开始。我一直在使用这个网站作为参考; https://levelskip.com/classic/Make-a-Text-Based-Game#gid=ci026bcb5e50052568&pid=make-a-text-based-game-MTc0NDU2NjE2MjQ1MDc3MzUy
system("cls");
int choiceOne_Path;
cout << "# What would you like to do?" << endl;
cout << "\t >> Enter '1' to follow the Chief?" << endl;
cout << "\t >> Enter '2' to find your own path?" << endl;
retry:
cout << "\nEnter your choice: ";
cin >> choiceOne_Path;
if(choiceOne_Path == 1)
{
cout << "\n!!!----------------------Chapter One: Escape----------------------!!!" << endl;
cout << "\nYou: Where are we going?" << endl;
cout << "Chief: Soon you will kNow. Just follow me." << endl;
cout << "# You run behind the chief." << endl;
}
else if(choiceOne_Path == 2)
{
cout << "\n!!!----------------------Chapter One: Escape----------------------!!!" << endl;
cout << "\nYou: I am going to find a way out!" << endl;
cout << "Chief: You are insane. You will get killed out there." << endl;
cout << "You: I have my secrets and I kNow my way out." << endl;
cout << "# You jump over the nearby broken fence" << endl;
cout << "# and run off towards the City Wall." << endl;
}
else
{
cout << "You are doing it wrong,warrior! Press either '1' or '2',nothing else!" << endl;
goto retry;
}
cout << "\n----------------------Press any key to continue----------------------" << endl;
_getch();
这是该站点显示为参考的代码,但我遇到了一些问题。主要使用“goto”命令仅适用于错误输入的整数。如果你在那里输入一个字母字符,它会变成一个无限循环。
在我寻找问题解决方案的过程中,我发现对“goto”功能有很多反对意见。现代代码基本上驳斥了它的使用,因为我理解它。所以在这一点上,我正在寻找一个不同的函数,它可以在输入一个不可用的字符时执行重做 cin 函数的任务。
如果在这种情况下没有该命令的自然替代品,我完全愿意使用完全不同的结构或系统。
解决方法
goto 的最佳替代品
retry:
// accept input
if (/* input predicate */)
{
// ...
}
else
{
// ...
goto retry;
}
这就是我们业内所说的“循环”。任何形式的循环结构都适用于这个例子,但这是一种罕见的 do-while 很好的情况。直接转换:
do
{
// accept input
if (/* input predicate */)
{
// ...
break;
}
else
{
// ...
}
} while(true);