如何在春季将 mybatis mapper 从 Java 迁移到 Kotlin?

问题描述

我有 MyBatis ORM 的 spring-boot 应用程序。在java中我写像

@Mapper
@Repository
public interface FooMapper {

    @SelectProvider(type = sqlProviderAdapter.class,method = "select")
    @Results(id = "resultFoo",value = {
            @Result(property = "rowId",column = "ROW_ID"),@Result(property = "created",column = "CREATED"),@Result(property = "lastUpdated",column = "LAST_UPD"),@Result(property = "fooId",column = "FOO_ID"),})
    Foo findBy(SelectStatementProvider selectStatement);

    @SelectProvider(type = sqlProviderAdapter.class,method = "select")
    @Results(value = {
            @Result(property = "rowId",})
    List<Foo> findListBy(SelectStatementProvider selectStatement);

    @SelectProvider(type = sqlProviderAdapter.class,method = "select")
    @Results(value = {
            @Result(property = "fooId",column = "FOO_ID")
    })
    List<String> findFooListBy(SelectStatementProvider selectStatement);

    @InsertProvider(type = sqlProviderAdapter.class,method = "insert")
    @Options(useGeneratedKeys = true,keyProperty = "record.rowId",keyColumn = "row_id")
    int insert(InsertStatementProvider<Foo> insertStatement);

    @UpdateProvider(type = sqlProviderAdapter.class,method = "update")
    int update(UpdateStatementProvider updateStatement);
}

这很好用!

但我需要将所有应用程序转换为 Kotlin。 我尝试了以下代码

@Mapper
@Repository
interface FooMapper {
    @SelectProvider(type = sqlProviderAdapter::class,method = "select")
    @Results(
        id = "resultReferralActivation",value = [Result(property = "rowId",Result(
            property = "created",column = "CREATED"
        ),Result(property = "lastUpdated",Result(
            property = "fooId",column = "FOO_ID"
        )]
    )
    fun findBy(selectStatement: SelectStatementProvider?): Foo?

    @SelectProvider(type = sqlProviderAdapter::class,method = "select")
    @Results(
        value = [Result(property = "rowId",column = "FOO_ID"
        )]
    )
    fun findListBy(selectStatement: SelectStatementProvider?): List<Foo?>?

    @SelectProvider(type = sqlProviderAdapter::class,method = "select")
    @Results(value = [Result(property = "fooId",column = "FOO_ID")])
    fun findFooListBy(selectStatement: InsertStatementProvider?): List<String?>?

    @InsertProvider(type = sqlProviderAdapter::class,keyColumn = "row_id")
    fun insert(insertStatement: InsertStatementProvider<Foo?>?): Int

    @UpdateProvider(type = sqlProviderAdapter::class,method = "update")
    fun update(updateStatement: UpdateStatementProvider?): Int
}

但它不起作用。如果我在 java 或 kotlin 类应用程序中尝试 awtowired FooMapper 时失败,并显示如下消息:can't find bean FooMapper。如果我评论了我的自动装配尝试,应用程序就会启动,但是当我检查 spring-bean-list 时,我看到 bean FooMapper 不存在。

如何将我的 Java 映射器转换为 Konlin?

感谢您的帮助!

解决方法

暂无找到可以解决该程序问题的有效方法,小编努力寻找整理中!

如果你已经找到好的解决方法,欢迎将解决方案带上本链接一起发送给小编。

小编邮箱:dio#foxmail.com (将#修改为@)

相关问答

Selenium Web驱动程序和Java。元素在(x,y)点处不可单击。其...
Python-如何使用点“。” 访问字典成员?
Java 字符串是不可变的。到底是什么意思?
Java中的“ final”关键字如何工作?(我仍然可以修改对象。...
“loop:”在Java代码中。这是什么,为什么要编译?
java.lang.ClassNotFoundException:sun.jdbc.odbc.JdbcOdbc...