尝试渲染文本时,我每隔一段时间初始化一次脚本就会崩溃

问题描述

所以我正在尝试自学 Python,并且作为一个项目,我正在尝试使用 pygame 创建游戏 Connect 4。我已经实现了一个显示所有图块坐标的调试功能,但是当我激活它时(将变量“调试”设置为“1”,每隔一次我尝试初始化脚本时,它就会变黑并崩溃。其他 50% 的情况下,它工作正常。当我禁用文本渲染时不会发生这种情况。但是,我不知道为什么会发生这种情况,并且在我的控制台中没有收到任何错误报告。

我正在通过 Anaconda3 发行版在 Spyder 中编写代码,使用 Python 3.7,使用 Pygame 2.0.1。

这是代码。有问题的线路似乎是 41-43,也许是 75-79,但我不知道可能有什么问题。有谁知道可能是什么问题?不同的字体也会发生这种情况。

import sys
import pygame

# ==== Settings ====

scalingFactor = 2 #Must be an integer

displayWidth = 320 * scalingFactor
displayHeight = 375 * scalingFactor
displaySize = [displayWidth,displayHeight]

Black = (0,0)
White = (255,255,255)
Grey = (255,255)
Red = (255,20,20)
Blue = (80,80,255)

player1 = Red
player2 = Blue
turnColor = player1 #Starting color

frameBackgroundColor = White
frameLatticeColor = Black
frameMargin = 5 * scalingFactor
gridWidth = 40 * scalingFactor
gridHeight = 40 * scalingFactor
columns = 7
rows = 6

fontColor = Black

debug = 1

# ==== Code ====

pygame.init()
screen = pygame.display.set_mode(displaySize)
clock = pygame.time.Clock()
pygame.display.set_caption('Connect Four')

if debug == 1: #Line 43 starts here
    #This somehow makes the script unstable and won't allow it to run every other time I try to initialize it.
    font = pygame.font.Font(None,24)

running = True

grid = []
for row in range(rows):
    grid.append([])
    for column in range(columns):
        grid[row].append(0)

def drawGrid():
    for row in range(rows):
        for column in range(columns):
            color = White
            pygame.draw.rect(screen,color,[(frameMargin + gridWidth) * column + frameMargin,(frameMargin + gridHeight) * row + frameMargin,gridWidth,gridHeight])
            
            if grid[row][column] == 1:
                pygame.draw.circle(screen,player1,[(frameMargin + gridWidth) * column + frameMargin + gridWidth // 2,(frameMargin + gridHeight) * row + frameMargin + gridHeight // 2],gridWidth // 2 - 5)
            if grid[row][column] == 2:
                pygame.draw.circle(screen,player2,gridWidth // 2 - 5)
            if debug == 1: #Line 75 starts here
                textString = str(row) + "," + str(column)
                textRender = font.render(textString,True,fontColor)
                screen.blit(textRender,((frameMargin + gridWidth) * column + frameMargin + 8,(frameMargin + gridHeight) * row + frameMargin + 8))

def validTile_check(validTile,pos,column,row):
    
    # Checks if registered click is on tile or on frame lattice
    if pos[0] % (gridWidth + frameMargin) <= frameMargin or pos[1] % (gridWidth + frameMargin) <= frameMargin:
        print("Click registered on",". Not on tile.")
    # Checks if registered click is within grid
    elif row > rows - 1 or column > columns - 1:
        print("Click registered on",". With grid coordinates:",row,". Not a tile.")
        validTile = 0
    # Checks if registered click is on bottom tile
    elif grid[row][column] == 0 and row == rows - 1:
        validTile = 1
    # Checks if registered click is on tile with placed piece in tile below
    elif grid[row][column] == 0 and grid[row + 1][column] > 0:
        validTile = 1
    else: 
        validTile = 0
        
    return validTile

def winCheck(winCondition,grid,row):
    
    winCondition = 0
    chain = 1     
    
    for n in range(1,3):
        if chain == 4:
            winCondition = 1
            break
        if row + n < rows:
            if grid[row][column] == grid[row + n][column]:
                chain += 1
            else:
                break

    return winCondition

while running:
    
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            
            pos = pygame.mouse.get_pos()
            column = pos[0] // (gridWidth + frameMargin)
            row = pos[1] // (gridHeight + frameMargin)
            validTile = 0
            winCondition = 0
            
            validTile = validTile_check(validTile,row)
            
            if validTile == 0:
                print("Click registered on",". Not a valid tile.")
            # Marks tile if clicked tile was unmarked.
            elif grid[row][column] == 0:
                if turnColor == player1:
                    grid[row][column] = 1
                    turnColor = player2
                elif turnColor == player2:
                    grid[row][column] = 2
                    turnColor = player1
                print("Click registered on",". Tile marked.")
            # Unmarks tile if clicked tile was marked.
            elif grid[row][column] > 0:
                grid[row][column] = 0
                print("Click registered on",". Tile unmarked.")
                
            winCheck(winCondition,row)
            
            if winCondition == 1:
                print("Winner!")
        
    screen.fill(Black)
    drawGrid()
    pygame.display.update()
    
    clock.tick(60)
    

pygame.quit()

控制台看起来像这样:

   In [2]: runfile('C:/Users/Admin/Documents/Connect4/Game/gameFrame.py',wdir='C:/Users/Admin/Documents/Connect4/Game')
    
   In [1]: runfile('C:/Users/Admin/Documents/Connect4/Game/gameFrame.py',wdir='C:/Users/Admin/Documents/Connect4/Game')
    pygame 2.0.1 (SDL 2.0.14,Python 3.7.4)
    Hello from the pygame community. https://www.pygame.org/contribute.html
    
   In [2]: runfile('C:/Users/Admin/Documents/Connect4/Game/gameFrame.py',Python 3.7.4)
    Hello from the pygame community. https://www.pygame.org/contribute.html
    
   In [1]:
    
   In [2]: runfile('C:/Users/Admin/Documents/Connect4/Game/gameFrame.py',wdir='C:/Users/Admin/Documents/Connect4/Game')

当它显示“来自 pygame 社区的你好”时。它可以工作,但当它什么都不显示,或者只显示“runfile()”行时,它就会崩溃。

解决方法

我仍然不完全知道出了什么问题,但似乎不是代码。我将 Python 版本更新为 3.9.5,并通过另一个下载器而不是 Anaconda3 下载了我正在使用的 IDE 的新版本。这些事情中的任何一个都可能解决了它,但它不再崩溃!