Python 在将 JsonL 转换为 CSV 文件时删除 .jsonl 扩展名

编程问答 2022-04-28

问题描述

我有一个脚本，可以将选定目录中的 jsonl 文件转换为另一个指定位置中的 csv 文件。但是，在将文件转换为 csv 格式时，最终创建的 csv 文件在 .csv 之前包含一个 .jsonl 扩展名（想想 file.jsonl.csv）关于如何在添加 csv 扩展名之前删除 .jsonl 扩展名的任何想法在后面?我希望我能够摆脱 csv 文件的 .jsonl 扩展名，因为它将来可能会令人困惑。谢谢！

创建的示例 CSV 文件： 20210531_CCXT_FTX_DOGEPERP.jsonl.csv

我的脚本：

import glob
import json
import csv
import time


start = time.time()
#import pandas as pd
from flatten_json import flatten

#Path of jsonl file
File_path = (r'C:\Users\Natthanon\Documents\Coding 101\Python\JSONL')
#reading all jsonl files
files = [f for f in glob.glob( File_path + "**/*.jsonl",recursive=True)]
i = 0

for f in files:
    with open(f,'r') as F:
        #creating csv files  
        with open(r'C:\Users\Natthanon\Documents\Coding 101\Python\CSV\\' + f.split("\\")[-1] + ".csv",'w',newline='') as csv_file:
            thewriter = csv.writer(csv_file)
            thewriter.writerow(["symbol","timestamp","datetime","high","low","bid","bidVolume","ask","askVolume","vwap","open","close","last","prevIoUsClose","change","percentage","average","baseVolume","quoteVolume"])

            for line in F:
                #flatten json files 
                data = json.loads(line)
                data_1 = flatten(data)
                #headers should be the Key values from json files that make Column header                    
                thewriter.writerow([data_1['symbol'],data_1['timestamp'],data_1['datetime'],data_1['high'],data_1['low'],data_1['bid'],data_1['bidVolume'],data_1['ask'],data_1['askVolume'],data_1['vwap'],data_1['open'],data_1['close'],data_1['last'],data_1['prevIoUsClose'],data_1['change'],data_1['percentage'],data_1['average'],data_1['baseVolume'],data_1['quoteVolume']])

解决方法

问题是因为你在写入新文件时没有去掉扩展名，像这样替换你创建的 csv 文件应该可以修复它

    file_name = f.rsplit("\\",1)[-1].replace('.jsonl','')
    with open(r'C:\Users\Natthanon\Documents\Coding 101\Python\CSV\\' + file_name + ".csv",'w',newline='') as csv_file:
csvcsvjsonjsonlinespythontype-conversion