理解反编译的solidity合约

问题描述

谁能帮我理解这个反编译的structure(list(person = c("Ane","Ane","John","John"),presence = c(1,1,1),result = c(5,6,4,8,7,9,2,3)),class = c("spec_tbl_df","tbl_df","tbl","data.frame"),row.names = c(NA,-9L),spec = structure(list( cols = list(person = structure(list(),class = c("collector_character","collector")),presence = structure(list(),class = c("collector_double",result = structure(list(),"collector"))),default = structure(list(),class = c("collector_guess",skip = 1L),class = "col_spec")) 函数

solidity

我了解 def storage: stor0 is uint256 at storage 0 def _fallback() payable: # default function require calldata.size >= 4 require not call.value if mem[0 len 28],uint32(call.func_hash) != 391405269: require mem[0 len 28],uint32(call.func_hash) == refund() static call 0xbb4cdb9cbd36b01bd1cbaebf2de08d9173bc095c.balanceOf(address owner) with: gas gas_remaining wei args stor0 require ext_call.success require return_data.size > 31 call 0xbb4cdb9cbd36b01bd1cbaebf2de08d9173bc095c.transfer(address to,uint256 value) with: gas gas_remaining wei args stor0,ext_call.return_data[0] require ext_call.success require return_data.size > 31 else: require not Mask(256,-160,_param1) call 0xbb4cdb9cbd36b01bd1cbaebf2de08d9173bc095c.transfer(address to,uint256 value) with: gas gas_remaining wei args _param1,10^15 require ext_call.success require return_data.size > 31 require ext_code.size(_param1) call _param1.0xfff6cae9 with: gas gas_remaining wei require ext_call.success balanceOf 函数调用 transfer 合同 (0xbb4..) 但什么是 WBNB 条件以及所有这些 {{1} }}s

附言合约部署在 https://bscscan.com/address/0x01f3c4bc6d027557c4b841e9f5cb19bb8a082b6a#code

谢谢

解决方法

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