mySql返回不正确的结果

问题描述

| 我有一个查询

SELECT date,SUM(cimpression) AS cimp,SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end 
AND (id = 21 AND id = 32 AND id = 12 AND id = 33)
GROUP BY date
ORDER BY date ASC;

此查询仅需要返回ID等于21、32、12和33的结果，但返回的结果不包含那些特定ID的结果，不确定到底是什么错误？有什么建议吗？     

解决方法

我认为您正在寻找的是：

SELECT date,SUM(cimpression) AS cimp,SUM(cclick) AS cclick
FROM stdaily
WHERE date BETWEEN :start AND :end 
AND id in (21,32,12,33) 
GROUP BY date 
ORDER BY date ASC;

这将返回结果，该结果的ID与

in

括号中包含的ID相同。     ,

id = 21 AND id = 32 AND id = 12 AND id = 33 

应该

id = 21 OR id = 32 OR id = 12 OR id = 33 

    ,您没有指定他应该在哪里检查那些ID，并且传递ID的方式也是错误的

WHERE date BETWEEN :start AND :end AND (id = 21 AND id = 32 AND id = 12 AND id = 33 )

应该是这样的：

SELECT date,SUM(cclick) AS cclick 
FROM stdaily 
WHERE date BETWEEN :start AND :end AND id IN (21,33 ) 
GROUP BY date 
ORDER BY date ASC

    ,我不知道您的数据的结构，但我很惊讶这会返回任何结果。 id如何同时为21和32？例如，如果我使用

SELECT * FROM users WHERE 1=1 AND (id = 10 AND id = 11);

即使有ID为10和11的用户，我也不会得到结果。 您应该使用OR或更好的IN（21,33）     ,您的查询不正确，因为ID不能同时包含所有这些值：

id = 21 AND id = 32 AND id = 12 AND id = 33 

先前的条件失败，结果为NULL。 尝试这个：

id = 21 OR id = 32 OR id = 12 OR id = 33