问题描述
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这可能吗 ?如果是,那么要涉及的表是什么。
解决方法
试试这个
select uc.table_name
from sys.user_cons_columns ucc
join sys.user_constraints uc
on uc.r_constraint_name = ucc.constraint_name
where constraint_type = \'R\'
and ucc.table_name = :1
and ucc.column_name = :2
哪里
:1 = referenced table
:2 = referenced column
, select * from user_constraints where r_constraint_name =<PK_NAME>
其中<PK_NAME>
是列的主键约束的名称
, 有两个候选查询可能在这里有所帮助:
http://www.alberton.info/oracle_meta_info.html
SELECT alc.constraint_name,CASE alc.constraint_type
WHEN \'P\' THEN \'PRIMARY KEY\'
WHEN \'R\' THEN \'FOREIGN KEY\'
WHEN \'U\' THEN \'UNIQUE\'
WHEN \'C\' THEN \'CHECK\'
END \"constraint_type\",alc.DELETE_RULE \"on_delete\",CASE alc.deferrable WHEN \'NOT DEFERRABLE\' THEN 0 ELSE 1 END \"deferrable\",CASE alc.deferred WHEN \'IMMEDIATE\' THEN 1 ELSE 0 END \"initially_deferred\",alc.search_condition,alc.table_name,cols.column_name,cols.position,r_alc.table_name \"references_table\",r_cols.column_name \"references_field\",r_cols.position \"references_field_position\"
FROM all_cons_columns cols
LEFT JOIN all_constraints alc
ON alc.constraint_name = cols.constraint_name
AND alc.owner = cols.owner
LEFT JOIN all_constraints r_alc
ON alc.r_constraint_name = r_alc.constraint_name
AND alc.r_owner = r_alc.owner
LEFT JOIN all_cons_columns r_cols
ON r_alc.constraint_name = r_cols.constraint_name
AND r_alc.owner = r_cols.owner
AND cols.position = r_cols.position
WHERE alc.constraint_name = cols.constraint_name
AND alc.constraint_name = \'TESTCONSTRAINTS_ID_FK\'
AND alc.table_name = \'TESTCONSTRAINTS2\';