将int分配给新int

问题描述

| 到目前为止，我有代码

- (void)CreatenewBlock:(int)blockCountToSpawn
{
    for (int i=0; i != blockCountToSpawn; i++) 
    {
        theBlockxCord = arc4random() % 4;
        theBlockyCord = arc4random() % 4;
        NSLog(@\"New Block with Cords (%i,%i)\",theBlockxCord,theBlockyCord);
    }

}

循环直到达到blockCountToSpawn的起点这完全符合我的期望，但是我想每次将theBlockxCord设置为一个新变量。因此，最终结果将类似于：

theBlockxCordOfBlock1=2
theBlockxCordOfBlock2=4
theBlockxCordOfBlock3=1
theBlockxCordOfBlock4=3

而不是每次都覆盖BlockXCord。对于奖励积分，是否可以通过数组调用它们，所以我不必继续这样做：

if (theBlockxCordOfBlock1 == 2 || theBlockxCordOfBlock3 == 2 ..etc)
{
   do stuff..
}

解决方法

您可以使用C数组或NSMutableArray。您必须先将3转换为4才能将其添加到数组中。

- (void)CreatenewBlock:(int)blockCountToSpawn
{
    NSMutableArray *blockXCoord = [NSMutableArray array]; // Retain it as needed.
    NSMutableArray *blockYCoord = [NSMutableArray array];
    for (int i=0; i != blockCountToSpawn; i++) 
    {
        [blockXCoord addObject:[NSNumber numberWithInt:(arc4random() % 4)];
        [blockYCoord addObject:[NSNumber numberWithInt:(arc4random() % 4)];
    }

    ...
}

如果要搜索2，请执行此操作

if ( [blockXCoord indexOfObject:[NSNumber numberWithInt:2]] != NSNotFound ) {
    ... do stuff
}

要么

if ( [blockXCoord containsObject:[NSNumber numberWithInt:2]] ) {
    ... do stuff
}

编辑

for ( int i = 0; i < [blockXCoord count]; i++ ) {
    NSPoint point = NSMakePoint([[blockXCoord objectAtIndex:i] intValue],[[blockYCoord objectAtIndex:i] intValue]);

    ... do something with the point.
}

, 对于第一个问题：将结果放入与任何C程序一样的常规数组中，或放入NSMutableArray中。 http://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSMutableArray_Class/Reference/Reference.html 关于第二个问题：如果使用NSMutableArray存储对象（例如，NSNumber），则可以调用containsObject:确定对象是否在数组中。 http://developer.apple.com/library/ios/documentation/cocoa/reference/foundation/Classes/NSArray_Class/NSArray.html#//apple_ref/occ/instm/NSArray/containsObject：

int int 配给