NSObject和NSMutableArray问题

问题描述

| 您好，我有这个NS对象：

@interface Checkin : NSObject {

    Nsstring *name;
    Nsstring *profID;
    Nsstring *time;
    Nsstring *lon;
    Nsstring *lat;
    Nsstring *country;
    Nsstring *city;
    Nsstring *place;
    Nsstring *photoURL;
    NSMutableArray *taggedID;
    NSMutableArray *taggedname;
}

@property(nonatomic,retain)Nsstring *name;
@property(nonatomic,retain)Nsstring *profID;
@property(nonatomic,retain)Nsstring *time;
@property(nonatomic,retain)Nsstring *lon;
@property(nonatomic,retain)Nsstring *lat;
@property(nonatomic,retain)Nsstring *country;
@property(nonatomic,retain)Nsstring *city;
@property(nonatomic,retain)Nsstring *place;
@property(nonatomic,retain)Nsstring *photoURL;
@property(nonatomic,retain)NSMutableArray *taggedID;
@property(nonatomic,retain)NSMutableArray *taggedname;

@end

现在，我想创建一个NSMutable数组，并在其中添加几个\“ Checkins \”。 当我这样做时：

 Checkin *checkinsA = [[NSObject alloc] init]; 

 NSDictionary *decodedJson = result;   
 NSArray *users = [decodedJson objectForKey:@\"data\"];

for(NSDictionary *user in users) {
    NSLog(@\"Created item: %@ \\n\",[user objectForKey:@\"created_time\"]);
     checkinsA.time = [Nsstring stringWithFormat:@\"%@\",[user objectForKey:@\"created_time\"]];
    NSDictionary *fromData = [user objectForKey:@\"from\"];
     NSLog(@\"user id is: %@ \\n\",[fromData objectForKey:@\"id\"]);
      checkinsA.profID = [fromData objectForKey:@\"id\"];

     NSLog(@\"user name is: %@\\n \",[fromData objectForKey:@\"name\"]);
      checkinsA.name =[fromData objectForKey:@\"name\"];

    NSDictionary *placeData = [user objectForKey:@\"place\"];
    NSDictionary *locationData = [placeData objectForKey:@\"location\"];
     NSLog(@\"City: %@ \\n\",[locationData objectForKey:@\"city\"]);
      checkinsA.city = [locationData objectForKey:@\"city\"];

     NSLog(@\"Country: %@ \\n\",[locationData objectForKey:@\"country\"]);
      checkinsA.country = [locationData objectForKey:@\"country\"];

     NSLog(@\"Latitude: %@ \\n\",[locationData objectForKey:@\"latitude\"]);
     checkinsA.lat = [locationData objectForKey:@\"latitude\"];

     NSLog(@\"Longitude: %@ \\n\",[locationData objectForKey:@\"longitude\"]);
     checkinsA.lon = [locationData objectForKey:@\"longitude\"];

     NSLog(@\"Place name: %@ \\n\",[placeData objectForKey:@\"name\"]);
     checkinsA.place = [placeData objectForKey:@\"name\"];

    NSDictionary *tagData = [user objectForKey:@\"tags\"];
    NSArray *tagDataArray = [tagData objectForKey:@\"data\"];
    for(NSDictionary *tagData2 in tagDataArray){
      NSLog(@\"tagged user id is: %@ \\n\",[tagData2 objectForKey:@\"id\"]);
        [checkinsA.taggedID addobject:[tagData2 objectForKey:@\"id\"]];
      NSLog(@\"tagged user name is: %@\\n \",[tagData2 objectForKey:@\"name\"]);
         [checkinsA.taggedname addobject:[tagData2 objectForKey:@\"name\"]];
    }

    [checkinArray addobject:checkinsA];
}

我收到错误消息：   -[NSObject setTime：]：无法识别的选择器已发送到的实例   checkinsA.time = [Nsstring stringWithFormat：@ \“％@ \”，[user objectForKey：@ \“ created_time \”]]]; 更改checkinsA.time checkins.id等值的正确方法是什么？     

解决方法

        之所以会出现此错误，是因为

checkinsA

不是

Checkin

对象，而是一个ѭ4si（因为这是您分配的对象），而

NSObject

没有

setTime

方法。尝试以下方法：

Checkin *checkinsA = [[Checkin alloc] init];