在Django 1.3中访问子类用户配置文件模块

问题描述

| 我正在尝试在django 1.3中创建两种用户类型。我将AUTH_PROFILE_MODULE划分为以下模型。

class Member(models.Model):
    ROLE_CHOICES = (
        (0,\'Guide\'),(1,\'Operator\'),)
    user = models.ForeignKey(User,unique=True)
    location = models.CharField(max_length=60)
    role = models.IntegerField(choices=ROLE_CHOICES)


class Guide(Member):
    bio = models.TextField(blank=True)
    experience = models.TextField(blank=True)
    image = models.ImageField(blank=True,upload_to=\'images\')
    fileupload = models.FileField(blank=True,upload_to=\'files\')

    def __unicode__(self):
        return self.user.username

    def get_absolute_url(self):
        return \'/profiles/guides/%s\' % self.user.username


class Operator(Member):
    bio = models.TextField(blank=True)
    image = models.ImageField(blank=True,upload_to=\'images\')

    def __unicode__(self):
        return self.user.username

    def get_absolute_url(self):
        return \'/profiles/operators/%s\' % self.user.username

我正在使用基于类的通用视图，并且可以使ListView适用于Guide和Operator模型，而DetailView无法使用。我的views.py如下：

class GuideDetailView(DetailView):
    model = Guide
    context_object_name = \'guide\'
    template_name = \'members/guide_detail.html\'


class GuideListView(ListView):
    model = Guide
    context_object_name = \'guides\'
    template_name = \'members/guide_list.html\'

知道可能缺少什么吗？     

解决方法

        提供一个查询集：

class GuideDetailView(DetailView):
    queryset = Guide.objects.all()

或重写DetailView的get方法：

class GuideDetailView(DetailView):
    def get(self):
        return \"Everything you want,maybe: Guide.object.get(id=1)\"

在您的urls.py中给出以下内容：

url(r\'^(?P<my_id>\\d)/$\',GuideDetailView.as_view(),),

您需要重写get，如下所示：

class GuideDetailView(DetailView):
    def get(self,request,**kwargs):
        # lookup Guide Id in your database and assign it object
        self.object = Guide.objects.get(pk=kwargs.get(\'my_id\'))
        # add object to your context_data,so that you can access via your template
        context = self.get_context_data(object=self.object)
        return self.render_to_response(context)