谷歌地图上标记和信息框的JSON结果

问题描述

|| JSON结果： [{\\“ Company \”：\“ Company1 \”，\“ Country \”：\“ US \”，\“ Phone \”：\“ 209-555-8400 \”，\“网站\”：\“ www.mywebsite.com \“，\”纬度“：35.782，\”经度\“：-120.2269}， {\“ Company \”：\“ Company2 \”，\“ Country \”：\“ US \”，\“ Phone \”：\“ 909-555-5500 \”，\“网站\”：\“ www .mywebsite.com \“，\”纬度\“：36.112782，\”经度\“：-111.52691}， {\“ Company \”：\“ Company3 \”，\“ Country \”：\“ US \”，\“ Phone \”：\“ 702-555-5200 \”，\“网站\”：\“ www .mywebsite.com \“，\”纬度\“：37.0427，\”经度\“：-112.1818}， {\“ Company \”：\“ Company4 \”，\“ Country \”：\“ US \”，\“ Phone \”：\“ 602-555-5600 \”，\“网站\”：\“ www .mywebsite.com \“，\”纬度“：38.4369，\”经度\“：-113.8671}， {\“ Company \”：\“ Company5 \”，\“ Country \”：\“ US \”，\“ Phone \”：\“ 800-555-4716 \”，\“ Website \”：\“ www .mywebsite.com \“，\”纬度\“：39.244946，\”经度\“：-114.211941}] 视图中的Javascript         var location = [\“如何在这里获取JSON结果\”]         var map = new google.maps.Map（document.getElementById（\'map_canvas \'），{             变焦：2             中心：新的google.maps.LatLng（40.0，-35.0），             mapTypeId：google.maps.MapTypeId.ROADMAP         }）;         var infowindow = new google.maps.InfoWindow（）;         var标记，i；         对于（i = 0; i 我需要这样的东西： var location = [\'Company1 209-555-8400 US www.mywebsite.com \'，35.78，-120.23]     

解决方法

看一下将json解析为对象。像JSON.net这样的东西会很有用。     ,你可以使用jQuery解析器

var dataJson = $.parseJSON(data);

然后遍历数组

for(var i=0;i<dataJson.length;i++)
{
   var company = dataJson[i].Company;
   ....
}

或者，如果您需要上面的ready字符串，则可以在服务器端进行设置

Type myType = myObject.GetType();
IList<PropertyInfo> props = new List<PropertyInfo>(myType.GetProperties());
String.Join(\" \",props.select(p => p.GetValue(yourObject,null)))

简明扼要

String.Join(\" \",(List<PropertyInfo>)(object.GetType().GetProperties()).select(p => p.GetValue(yourObject,null)))