MySQL单表，根据多行选择值

问题描述

| 从下表中，我将如何选择具有attributeIds特定组合的所有animalIds，例如如果我提供了attributeIds 455和685，我希望可以取回animalIds 55和93 表名：animalAttributes

id      attributeId     animalId
1       455             55
2       233             55
3       685             55
4       999             89
5       455             89
6       333             93
7       685             93
8       455             93

我有以下查询似乎有效，但是，我不确定是否有更可靠的方法？

  SELECT animalId
    FROM animalAttributes
   WHERE attributeId IN (455,685)
GROUP BY animalId 
  HAVING COUNT(DISTINCT attributeId) = 2;

    

解决方法

        如果您确实想要准确的结果，则可以采用如下的防呆方法：

select distinct base.animalId
from animalAttributes base
join animalAttributes a on base.animalId = a.animalId
     and a.attributeId = 455
where base.attributeId = 685

如果以后需要3个匹配的属性，则可以添加另一个联接：

select distinct base.animalId
from animalAttributes base
join animalAttributes a on base.animalId = a.animalId
     and a.attributeId = 455
join animalAttributes b on base.animalId = b.animalId
     and b.attributeId = 999
where base.attributeId = 685

    ,        

SELECT DISTINCT `animalId` FROM `animalAttributes` WHERE `attributeId` = 455
INTERSECT
SELECT DISTINCT `animalId` FROM `animalAttributes` WHERE `attributeId` = 685

    ,        

SELECT DISTINCT animalId
FROM animalAttributes
WHERE attributeId IN (455,685)

要么

SELECT animalId
FROM animalAttributes
WHERE attributeId IN (455,685)
GROUP BY animalId