通过PHP的基于Drupal的SQL查询：计数t1加入t2

问题描述

|| 我有两个这样的表：

table {node}
`nid`,`uid`,`type`
 1    1   basketball
 2    1   basketball
 3    1   football
 4    2   football
 5    2   basketball

table {strato_ticket}
`tid`,`author_uid`,`purpose`,`active`
 1      1   \'Ticket to a basketball game\' TRUE
 2      1   \'Ticket to a football game\'   TRUE
 3      2   \'Ticket to a football game\'   FALSE

我想生成一个报告，该报告计算每种类型的节点的数量，然后计算每个用户与该类型的节点相关联的活动票证的数量。 我的解决方案使用了sql和PHP的组合：对于我感兴趣的每种节点，我都有一个PHP循环，从而简化了SQL查询，并将其从“类型”转换为“用途”，例如

$node_types = array(\'basketball\',\'football\');
foreach($node_types as $node){
  switch($type){
    case \'basketball\':
      $purpose = array(\'Ticket to a basketball node\');
      break;
    case \'football\':
      $purpose = array(\'Ticket to a football game\');
      break;
  }
  $where = \" WHERE ({strato_ticket}.`purpose` = \'\"
    .implode(\"\' OR {strato_ticket}.`purpose` = \'\",$purpose).\"\')\";

最后我有麻烦的地方，SQL查询。当我只计算每个用户拥有的节点时，它运行良好：

$query = \"
      SELECT uid,count( * ) AS nodes_owned
      FROM {node} WHERE `type` = \'$type\'
      GROUP BY uid ORDER BY nodes_owned DESC
      \";
  $query = db_query($query);

output:
Now displaying info for basketball.
uid nodes_owned
 1       2
 2       1
Now displaying info for football.
uid nodes_owned
 1       1
 2       1

但是，现在我需要查询另一个表strato_ticket，事情变得复杂了，我的查询返回FALSE而不抛出错误（我认为）。

 $query = \"
    SELECT count(*) as tickets
    FROM {strato_ticket} INNER JOIN (
        SELECT node.uid,count( * ) AS nodes_owned
        FROM {node} WHERE `type` = \'$type\'
        GROUP BY uid
      ) AS {nodecount}
      ON {strato_ticket}.`author_uid` = {nodecount}.`uid`
      $where
      GROUP BY nodecount.uid ORDER BY nodecount.nodes_owned DESC
      \";
  $query = db_query($query);

我对sql不太满意，也不太确定它的中断方式。可以使用一点帮助吗？ 理想地想看

uid nodes_owned tickets
//basketball
 1       2        1
 2       1        0
//football 
 1       1        1
 2       1        0

    

解决方法

除了占位符（我可以稍后再讲）之外，我认为这可以解决问题。

$form = array();
$node_types = array(\'basketball\',\'football\');
// if($user->uid == 1){
  $form[$type][] = array(\'#value\'=>\"Showing how many of each node type each user owns.\".\'<br/>\');
  foreach($node_types as $type){
  // Count the number of nodes each user owns of $type.
  $form[$type][] = array(\'#value\'=>\"Now displaying info for $type\".\'s. <br/>\');
  switch($type){
    case \'basketball\':
      $purpose = array(\'ticket to a basketball game\',\'basketball\');
    break;
    case \'football\':
      $purpose = array(\'ticket to a football game\');
    break;
  }
  $purpose = implode(\"\',\'\",$purpose);
  //@todo : Make a temporary table to query against so I\'m not hitting node table multiple times.
  $ticketquery = \"
    SELECT author_uid,purpose,COUNT( * ) AS invitees_accepted
    FROM {strato_ticket}
    WHERE purpose IN (\'$purpose\')
    GROUP BY author_uid,`purpose`
  \";
  $nodequery = \"
    SELECT node.uid,count( * ) AS nodes_owned,type
    FROM {node}
    WHERE `type` IN (\'$type\')
    GROUP BY uid,type\";
  $query = \"
    SELECT * FROM
    ($nodequery) AS nt
    JOIN
    ($ticketquery) AS tt
    ON nt.uid = tt.author_uid
    GROUP BY nt.uid ORDER BY nt.nodes_owned DESC
   \";

  drupal_set_message(\'Query is <br/>\'.$query);
  //return;
  $query = db_query($query);
  $first = true;
  while ($rec = db_fetch_object($query)){
    if($first){
      $form[$type][] = array(\'#value\'=>\"And the winner is: \".print_r($rec,true).\'<br/>\');
      $first = false;
    }
    else {
     $form[$type][] = array(\'#value\'=>print_r($rec,true).\'<br/>\');
    }
  }
 // }
}