问题描述
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我应该得到一个文件并扫描信息。当我尝试打印时,我扫描的大多数信息都丢失或被切断。这是我的代码:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
typedef struct profile {
char gender;
float soc;
char name[20];
char name2[20];
int age;
char job[20];
float income;
char M_hob[20];
char m_hob[20];
int height;
int weight;
char relig[20];
} PROFILE;
int main(void)
{
int i,count;
char file[30],ssn[10];
FILE *fin;
PROFILE members[50];
printf(\"SSN: \");
scanf(\"%s\",ssn);
printf(\"Name of file of records: \");
scanf(\"%s\",file);
fin = fopen(file,\"r\");
if ((fin == NULL)) {
printf(\"Can\'t Open File\");
exit(1);
}
i = 0;
while (fscanf(fin,\"%c\",&members[i].gender) != EOF) {
fscanf(fin,\"%f\",&members[i].soc);
fscanf(fin,\"%s\",members[i].name);
fscanf(fin,members[i].name2);
strcat(members[i].name,members[i].name2);
fscanf(fin,\"%d\",&members[i].age);
fscanf(fin,members[i].job);
fscanf(fin,&members[i].income);
fscanf(fin,members[i].M_hob);
fscanf(fin,members[i].m_hob);
fscanf(fin,&members[i].height);
fscanf(fin,&members[i].weight);
fscanf(fin,members[i].relig);
fscanf(fin,&members[i].space);
i++;
}
fclose(fin);
count = i;
for (i = 0; i <= count; i++) {
printf(\"%c\\n\",members[i].gender);
printf(\"%.0f\\n\",members[i].soc);
printf(\"%s\\n\",members[i].name);
printf(\"%d\\n\",members[i].age);
printf(\"%s\\n\",members[i].job);
printf(\"%.0f\\n\",members[i].income);
printf(\"%s\\n\",members[i].M_hob);
printf(\"%s\\n\",members[i].m_hob);
printf(\"%d\\n\",members[i].height);
printf(\"%d\\n\",members[i].weight);
printf(\"%s\\n\",members[i].relig);
}
return 0;
}
我要扫描的两段内容:
M
111223333
Rob Low
47
Actor
1000000
Dancing
Painting
63
165
Atheist
M
123456789
Bob Mitchell
77
Driver
25000
Baseball
Cooking
72
275
None
以及部分打印出来的内容:
M
111223336
Rob
47
Actor
1000000
Dancing
Painting
63
165
Atheist
0
M
0
Bob
0
Mitchell
77
0
0
Driver
2
5000
Baseball
72
275
0
ne
如您所见,第一个被完全扫描,但其余的则是越野车。
解决方法
如果必须使用
fscanf()
,请检查每个返回值。
担心循环前部的%c
在第二个循环中会获得换行符或大约它。
您最好将每一行读为一个大字符串,然后在其中加上ѭ5。这至少避免了对换行符的混淆。 (由于它们处理换行符的方式,我不会用bar来触及scanf()
或fscanf()
-还是不行。)