从代码后面填充ASPxTextBox和ASPxListBox

问题描述

|| 即时通讯为项目使用Devexpress ASPxGridView，但在使用数据填充自定义EditForm时遇到问题。 看起来如下

<Templates>
    <EditForm>
        Company Name:
        <dx:ASPxTextBox ID=\"CompanyName\" runat=\"server\" Value=\"<% #Bind(\'CompanyName\') %>\" />
        Parent:
        <dx:ASPxListBox ID=\"ParentGuid\" runat=\"server\" Value=\"<% #Bind(\'ParentGuid\') %>\" />
    </EditForm>
</Templates>

通常我会写类似

protected void ASPxGridView1_StartRowEditing(object sender,DevExpress.Web.Data.ASPxStartRowEditingEventArgs e)
{
    var CompanyList = db.companies.OrderBy(x => x.CompanyName).ToList();
    ASPxListBox ParentGuid = (ASPxListBox)ASPxGridView1.FindControl(\"ParentGuid\");
    ParentGuid.DataSource = CompanyList;
    ParentGuid.DataBind();

    ASPxTextBox CompanyName = (ASPxTextBox)ASPxGridView1.FindControl(\"CompanyName\");
    CompanyName.Text = \"Some company name\";
}

但这行不通。有什么建议从哪里开始？该文档并没有真正涵盖自定义表单：/ 谢谢！ ==更新== 尝试使用onhtmleditformcreated = \“ ASPxGridView1_HtmlEditFormCreated \”和方法

protected void ASPxGridView1_HtmlEditFormCreated(object sender,ASPxGridViewEditFormEventArgs e)
{
    Control CompanyName = ASPxGridView1.FindEditFormTemplateControl(\"CompanyName\");
    if (CompanyName != null)
    {
        ASPxTextBox CompanyNameEdit = CompanyName as ASPxTextBox;
        CompanyName.Text = \"Some Co\";
    }

}

我使用Value = \“ <％#Bind（\'CompanyName \'）％> \”的事实使事情有些混乱。如果我删除“绑定”，则将填充框，但随后无法获取其中的数据。可以解决吗？     

解决方法

        您应该使用稍微不同的方法： 使用HtmlEditFormCreated事件来设置编辑器属性。要获取编辑器实例，请使用gridView \的FindEditFormTemplateControl方法。     ,        答案是... 填充名为CompanyList的ASPxComboBox

protected void ASPxGridView1_HtmlEditFormCreated(object sender,ASPxGridViewEditFormEventArgs e)
{
    Control ParentGuidControl = ASPxGridView1.FindEditFormTemplateControl(\"ParentGuid\");
    if (ParentGuidControl != null)
    {
        ASPxComboBox ParentGuid = (ASPxComboBox)ParentGuidControl;

        var CompanyList = db.companies.OrderBy(x => x.CompanyName);
        ParentGuid.TextField = \"CompanyName\";
        ParentGuid.ValueField = \"CompanyGuid\";
        ParentGuid.DataSource = CompanyList;
        ParentGuid.DataBind();
    }
}

但！ 如果您有一个像我一样的自定义表格

<Templates>
    <EditForm>
        Company Name:
        <dx:ASPxTextBox ID=\"CompanyName\" runat=\"server\" Value=\"<% #Bind(\'CompanyName\') %>\" />
        Parent:
        <dx:ASPxComboBox ID=\"ParentGuid\" runat=\"server\" Value=\"<% #Bind(\'ParentGuid\') %>\" />
    </EditForm>
</Templates>

您将无法从代码后面填充它，因此#bind方法将覆盖所有其他传入值。但是，如果您不打算从后面的代码中填充它们，那么这是一个巧妙的技巧来获取数据...

protected void ASPxGridView1_RowInserting(object sender,DevExpress.Web.Data.ASPxDataInsertingEventArgs e)
{
    IDictionaryEnumerator enumerator = e.NewValues.GetEnumerator();

    string CompanyName = string.Empty;
    Guid ParentGuid = Guid.Empty;

    enumerator.Reset();
    while (enumerator.MoveNext())
        if (enumerator.Key.ToString() == \"CompanyName\")
            CompanyName = enumerator.Value.ToString();
        else if (enumerator.Key.ToString() == \"ParentGuid\")
            ParentGuid = new Guid(enumerator.Value.ToString());

    // Do insert trick here

}

但是，如果您想从代码后面填充一些表单值，请确保EditForm中没有#bind方法

<Templates>
    <EditForm>
        Company Name:
        <dx:ASPxTextBox ID=\"CompanyName\" runat=\"server\" />
        Parent:
        <dx:ASPxComboBox ID=\"ParentGuid\" runat=\"server\" />
    </EditForm>
</Templates>

按照文章顶部的说明进行填充，并获取类似的值

protected void ASPxGridView1_RowInserting(object sender,DevExpress.Web.Data.ASPxDataInsertingEventArgs e)
{
    string CompanyName = string.Empty;
    Guid ParentGuid = Guid.Empty;

    // This method is a bit more secure
    Control CompanyNameControl = ASPxGridView1.FindEditFormTemplateControl(\"CompanyName\");
    if (CompanyNameControl != null)
    {
        ASPxTextBox CompanyNameTb = (ASPxTextBox)CompanyNameControl;
        CompanyName = CompanyNameTb.Text.ToString();
    }

    // A bit less secure,but lesser code
    ASPxComboBox ParentGuidControl = (ASPxComboBox)ASPxGridView1.FindEditFormTemplateControl(\"ParentGuid\");
    ParentGuid = new Guid(ParentGuidControl.SelectedItem.Value.ToString());

    // Do insert...

}

玩得开心