问题描述
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当我运行下面给出的程序时,出现下面的错误
错误:
错误域= NSURLErrorDomain代码= -1000 \“错误URL \” UserInfo = 0x5948b80 {NSUnderlyingError = 0x5948ac0 \“错误URL \”,NSLocalizedDescription =错误URL}
我需要做的建议我
感谢你..
代码如下
@implementation WebSampleViewController
- (void)viewDidLoad
{
[super viewDidLoad];
dataWebService = [[NSMutableData data] retain];
NSMutableuRLRequest *request = [[NSMutableuRLRequest requestWithURL:[NSURL URLWithString:@\" http://www.googleapis.com/customsearch\"]] retain];
NSURLConnection *myConnection = [NSURLConnection connectionWithRequest:request delegate:self];
[myConnection start];
[super viewDidLoad];
}
- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{
[dataWebService setLength:0];
}
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
[dataWebService appendData:data];
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
Nsstring *responseString = [[Nsstring alloc] initWithData:dataWebService encoding:NSUTF8StringEncoding];
NSLog(@\"Response: %@\",responseString);
[responseString release];
[dataWebService release];
}
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
{
NSLog(@\"Error during connection: %@\",[error description]);
}
解决方法
您不应该“ 1”请求类型为NSMutableURLRequest的实例。
字符串URL中的前导空格。
使用以下代码。
NSMutableURLRequest *request = [[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@\"http://www.googleapis.com/customsearch\"]];
我认为,您应该检查URL,然后输入与iPhone相同的“未找到”字样。
, 请尝试在URL字符串的开头没有空格的情况下进行尝试。
, 您必须在网址中删除空格