使用NSURLConnection WebService

问题描述

| 当我运行下面给出的程序时,出现下面的错误 错误错误域= NSURLErrorDomain代码= -1000 \“错误URL \” UserInfo = 0x5948b80 {NSUnderlyingError = 0x5948ac0 \“错误URL \”,NSLocalizedDescription =错误URL} 我需要做的建议我 感谢你.. 代码如下
@implementation WebSampleViewController


- (void)viewDidLoad
{
    [super viewDidLoad];

    dataWebService = [[NSMutableData data] retain];


    NSMutableuRLRequest *request = [[NSMutableuRLRequest requestWithURL:[NSURL URLWithString:@\" http://www.googleapis.com/customsearch\"]] retain];


    NSURLConnection *myConnection = [NSURLConnection connectionWithRequest:request delegate:self];

    [myConnection start];    

    [super viewDidLoad];
}



- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response 
{

    [dataWebService setLength:0];

}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{

    [dataWebService appendData:data];

}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection 

{

    Nsstring *responseString = [[Nsstring alloc] initWithData:dataWebService encoding:NSUTF8StringEncoding];

    NSLog(@\"Response: %@\",responseString);

    [responseString release];

    [dataWebService release];

}

- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
{

    NSLog(@\"Error during connection: %@\",[error description]);
}
    

解决方法

        您不应该“ 1”请求类型为NSMutableURLRequest的实例。 字符串URL中的前导空格。 使用以下代码。
NSMutableURLRequest *request = [[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@\"http://www.googleapis.com/customsearch\"]];
我认为,您应该检查URL,然后输入与iPhone相同的“未找到”字样。     ,        请尝试在URL字符串的开头没有空格的情况下进行尝试。     ,        您必须在网址中删除空格