问题描述
|
我正在使用json连接到Web服务。
我使用nsurl连接进行连接。我有json响应字符串...我需要解析它。
当我尝试解析它时，出现以下错误：
dyld：找不到符号：_CFXMLNodeGetInfoPtr
这是相关的源代码：
// Using NSURLConnection
- (void)viewDidLoad
{
[super viewDidLoad];
dataWebService = [[NSMutableData data] retain];
NSMutableuRLRequest *request = [[NSMutableuRLRequest requestWithURL:[NSURL URLWithString:@\"https://www.googleapis.com/customsearch/v1?key=AIzaSyDzl0Ozijg2C47iYfKgBWWkAbZE_wCJ-2U&cx=017576662512468239146:omuauf_lfve&q=lectures&callback=handleResponse\"]]retain];
NSURLConnection *myConnection = [NSURLConnection connectionWithRequest:request delegate:self];
[myConnection start];
[super viewDidLoad];
}
- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{
[dataWebService setLength:0];
}
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
[dataWebService appendData:data];
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
Nsstring *responseString = [[Nsstring alloc] initWithData:dataWebService encoding:NSUTF8StringEncoding];
NSLog(@\"Response: %@\",responseString);
[responseString release];
[dataWebService release];
}
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
{
NSLog(@\"Error during connection: %@\",[error description]);
}
// Parse JSON
- (void)requestCompleted:(ASIHTTPRequest *)request
{
Nsstring *responseString = [request responseString];
NSDictionary *dictionary = [responseString JSONValue];
NSDictionary *dictionaryReturn = (NSDictionary*) [dictionary objectForKey:@\"request\"];
Nsstring *total = (Nsstring*) [dictionaryReturn objectForKey:@\"totalResults\"];
NSLog(@\"totalResults: %@\",total);
int count = [[dictionaryReturn objectForKey:@\"count\"] intValue];
NSLog(@\"count: %d\",count);
}
解决方法
JSON响应字符串不是有效的字符串，这就是您收到错误的原因。
使用以下链接检查从Web服务作为响应发送的JSON字符串是否有效。
JSONLint