android平板电脑上的Listview

问题描述

| 我的平板电脑布局有两个列表视图，一个右，一个左。当我单击一个组（左侧列表的项目）时，组将显示在另一个列表（groupsList）中。现在，当我单击该特定区域中的组列表时，需要显示其他布局。 那么如何进行呢？ 下面是我的代码：

  package com.list.viewer;

import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.AdapterView;
import android.widget.BaseAdapter;
import android.widget.ImageView;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.AdapterView.OnItemClickListener;

public class HealthPlan extends Activity 
{

private String[] list1 = { \"Group\",\"Opportunities\",\"Contacts\",\"Activities\",\"Quotes\"};
private String[] list2 = { \"\",\"\",\"\"};

private Integer[] imgid = {R.drawable.accounts,R.drawable.s,R.drawable.contacts,R.drawable.activities,R.drawable.s};

static final Integer[] aimgid = {R.drawable.activities_60,R.drawable.activities_60,R.drawable.activities_60};

static final String[] a1 = new String[] {\"1-96XO56\",\"1-96XOPL\",\"1-96Xomr\",\"1-96XOKM\"};

static final String[] a2 =  new String[] {\"Open\",\"Closed\",\"Cancelled\",\"Open\"};

static final Integer[] cimgid = {R.drawable.contacts_60,R.drawable.contacts_60,R.drawable.contacts_60};

static final String[] c1 = new String[] {\"Denning\",\"Guido\",\"Castro\",\"Heath\"};

static final String[] c2 =  new String[] {\"[email protected]\",\"[email protected]\"};

static final Integer[] gimgid = {R.drawable.accounts_60,R.drawable.accounts_60,R.drawable.accounts_60};

static final String[] g1 = new String[] {\"La Maison Blanche Bakery\",\"(NSCC) FRONTIER @R_319_4045@I\",\"american Diamond Tool,Inc\",\"OCH Test 20100831\"};

static final String[] g2 =  new String[] {\"PRVS - Private Sector\",\"PBLS - Public Sector\",\"PRVS - Private Sector\",\"NATL - National Account\"};

static final Integer[] qimgid = {R.drawable.health,R.drawable.health,R.drawable.health};

static final String[] q1 = new String[] {\"1-7LY9JK\",\"1-7GRMRO\",\"1-7FCJBR\",\"1-7GRMP4\"};

static final String[] q2 =  new String[] {\"In-Progress\",\"Created\",\"Install In Progress\",\"Installed\"};

static final Integer[] oimgid = {R.drawable.health,R.drawable.health};

static final String[] o1 = new String[] {\"Long Term Care\",\"HMO Blue Choice Value\",\"Drug\",\"Long Term Care\"};

static final String[] o2 =  new String[] {\"New Business - Exclusive\",\"Win Exclusive\",\"New Business - Nonexclusive\",\"Change Product / Service\"};

private ListView lister1;
private ListView lister2;

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    lister1 = (ListView) findViewById(R.id.ListView1);
    lister2 = (ListView) findViewById(R.id.ListView2);

    ItemsAdapter itemsAdapter = new ItemsAdapter(HealthPlan.this,R.layout.row,list1,list2,imgid);
    lister1.setAdapter(itemsAdapter);

    lister2.setAdapter(new ItemsAdapter(HealthPlan.this,g1,g2,gimgid));

    lister2.setonItemClickListener(new OnItemClickListener() 
    {
        @Override
        public void onItemClick(AdapterView<?> arg0,View arg1,int position,long arg3) 
        {


        }

    });

    lister1.setonItemClickListener(new OnItemClickListener() 
    {
        @Override
        public void onItemClick(AdapterView<?> arg0,long arg3)
        {
            String[] lister = null;
            String[] lister1 = null;
            Integer[] image = null;
            switch (position) 
            {
            case 0:
                lister = g1;
                lister1 = g2;
                image = gimgid;
                break;
            case 1:
                lister = o1;
                lister1 = o2;
                image = oimgid;
                break;
            case 2:
                lister = c1;
                lister1 = c2;
                image = cimgid;
                break;
            case 3:
                lister = a1;
                lister1 = a2;
                image = aimgid;
                break;
            case 4:
                lister = q1;
                lister1 = q2;
                image = qimgid;
                break;
            default:
                lister = g1;
                lister1 = g2;
                image = gimgid;
            }
            lister2.setAdapter(new ItemsAdapter(HealthPlan.this,lister,lister1,image));
        }
    });
}

private class ItemsAdapter extends BaseAdapter 
{
    String[] items;
    String[] items1;
    Integer[] images;

    public ItemsAdapter(Context context,int textViewResourceId,String[] items,String[] items1,Integer[] images)
    {
        this.items = items;
        this.items1 = items1;
        this.images=images;
    }

    @Override
    public View getView(final int position,View convertView,ViewGroup parent) 
    {
        TextView mDescription;
        TextView mDescription1;
        View view = convertView;
        ImageView image;

        if (view == null)
        {
            LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            view = vi.inflate(R.layout.row,null);
        }

        image = (ImageView) view.findViewById(R.id.icon);
        mDescription = (TextView) view.findViewById(R.id.tt1);
        mDescription1 = (TextView) view.findViewById(R.id.tt2);
        mDescription.setText(items[position]);
        mDescription1.setText(items1[position]);
        image.setimageResource(images[position]);
        return view;
    }

    public int getCount()
    {
        return items.length;
    }

    public Object getItem(int position)
    {
        return position;
    }

    public long getItemId(int position) 
    {
        return position;
    }
}

}     

解决方法

        就显示第三个列表而言，实际上很容易做到，并且适合您的模式。在您的布局文件中，定义第三个列表，但是将其可见性设置为“消失”，从而使其不再可见。现在，当您在第二个列表中单击时，可以设置第三个列表的可见性以使其可见：

Lister.setVisibility (View.VISIBLE) ;