我如何使用与上一个相同的对象引用在可变数组中添加新的对象实例

问题描述

||
//viewController.h file
//---------------------
#import <UIKit/UIKit.h>

@interface ItemClass : NSObject 
{
    Nsstring* name;
}
@property (nonatomic,retain) Nsstring* name;
@end



@interface PlaceClass : ItemClass 
{
    Nsstring* coordinates;
}
@property (nonatomic,retain) Nsstring* coordinates;
@end




@interface viewController : UIViewController {
    NSMutableArray* placesMutArray;
    PlaceClass* currentPlace;
}

@end

//viewController.m file
//------------------------

#import \"viewController.h\"
@implementation ItemClass
@synthesize name;
@end


@implementation PlaceClass
@synthesize coordinates;
@end


@implementation viewController

- (void)viewDidLoad {
    [super viewDidLoad];

    placesMutArray = [[NSMutableArray alloc] init];
    currentPlace = [[PlaceClass alloc] init];

    // at some point in code the properties of currentPlace are set
    currentPlace.name = [Nsstring stringWithFormat:@\"abc\"];
    currentPlace.coordinates = [Nsstring stringWithFormat:@\"45.25,24.22\"];
    // currentPlace added to mutable array
    [placesMutArray addobject:currentPlace];

    //Now the properties of currentPlace are changed
    currentPlace.name = [Nsstring stringWithFormat:@\"def\"];
    currentPlace.coordinates = [Nsstring stringWithFormat:@\"45.48,75.25\"];
    // again currentPlace added to mutable array
    [placesMutArray addobject:currentPlace];

    for(PlaceClass* x in placesMutArray)
    {
        NSLog(@\"Name is : %@\",x.name);
    }

}
@end
输出我得到:
Name is : def
Name is : def
期望的输出
Name is : abc
Name is : def
我希望placesMutArray具有两个单独的对象(每个对象分配了单独的内存空间),每个对象都有自己的一组“名称”和“坐标”属性。但是上面的代码显然只是更改了同一对象“ currentPlaces”的属性,并且其引用两次添加到了数组中。暗示我只在内存中分配了一个对象。当我使用快速枚举和NSlog遍历数组时,这两个元素的name属性都会两次出现最后一次设置的值。 采用NScopying协议可以解决问题吗?
[placesMutArray addobject:[currentPlace copy]];
如果是,那我应该怎么做?我尝试过,但是我遇到很多错误。     

解决方法

        您使用的是同一实例,这是正确的。您只需要制作一个新的。 尝试这个 :
// Create a second PlaceClass before setting it\'s properties to \'def\'
currentPlace = [[PlaceClass alloc] init];
currentPlace.name = [NSString stringWithFormat:@\"def\"];
currentPlace.coordinates = [NSString stringWithFormat:@\"45.48,75.25\"];
将对象添加到数组不会为您复制该对象-只是意味着该数组知道该对象。在将第一个currentPlace添加到数组后,您的
currentPlace
变量仍指向第一个对象,因此当开始设置新名称和坐标时,您将更新第一个,而不创建新对象。     ,        您仅创建了一个PlaceClass对象(currentPlace),然后将对此PlaceClass对象的2个引用添加到了数组中。您必须创建第二个对象
secondPlace = [[PlaceClass alloc] init];
secondPlace.name = [NSString stringWithFormat:@\"def\"];
secondPlace.coordinates = [NSString stringWithFormat:@\"45.48,75.25\"];
[placesMutArray addObject:secondPlace];
要么
secondPlace = [currentPlace mutableCopy];
secondPlace.name = [NSString stringWithFormat:@\"def\"];
secondPlace.coordinates = [NSString stringWithFormat:@\"45.48,75.25\"];
[placesMutArray addObject:secondPlace];
无论哪种方式,请记住在使用分配,复制或保留时释放对象
[secondPlace release];