问题描述
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尝试以编程方式生成许多按钮时出现该错误。我没有ctl02 ..为什么会出现该错误?
Button pgs = new Button();//Create New Topic
pgs.Width = 20;
pgs.Command += obtainTopicsPerPage_Click;
pgs.CommandName = tPage.ToString();
pgs.Text = tPage.ToString();
btns.Add(tPage.ToString());
buttons.Add(pgs);
我创建了几个按钮并遍历列表(按钮)。然后我得到那个错误:(。...为什么?
完整设计:
int maximumTopicPages;
int tPage;
int questionNumber=1;
Dictionary<string,List<DisplayAllQuestionsTable>> tPages;
List<Button> buttons = new List<Button>();
protected void Answer_Click(object sender,EventArgs e)
{
ViewState[\"SeekPressed\"] = \"pressed\";
tPages = new Dictionary<string,List<DisplayAllQuestionsTable>>();
string subTopic = SubTopicDropDownList.SelectedItem.Value;
List<DisplayAllQuestionsTable> threadsByTopic = new List<DisplayAllQuestionsTable>();
List<string> btns = new List<string>();
foreach (var topicKeys in postsByTopic)
{
if (topicKeys.Key == subTopic)
{
foreach (var item in postsByTopic[topicKeys.Key])
{
questionNumber++;
maximumTopicPages++;
threadsByTopic.Add(item);//Adds All DisplayAllTables objects
//if there are 20 add a button.
if (maximumTopicPages == 20)
{
tPages.Add(tPage++.ToString(),threadsByTopic);//Add a number to the page each time,with a DisplayTable object
//new Button
Button pgs = new Button();//Create New Topic
pgs.Width = 20;
pgs.Command += obtainTopicsPerPage_Click;
pgs.CommandName = tPage.ToString();
pgs.Text = tPage.ToString();
btns.Add(tPage.ToString());
buttons.Add(pgs);
maximumTopicPages = 0;
threadsByTopic.Clear();
}
}//number of questions per page
if (!tPages.ContainsKey((questionNumber / 20).ToString()))
{
tPages.Add((questionNumber / 20).ToString(),threadsByTopic);//If A button is missing add it.
}
}
将按钮添加到表的方式:
void MyButtonTable()
{
TableRow myTableRow = new TableRow();
HtmlForm form = new HtmlForm();
form.Attributes.Add(\"runat\",\"server\");
Page.Controls.Add(form);
foreach (var item in buttons)
{
TableCell myTableCell = new TableCell();
form.Controls.Add(item);
myTableCell.Controls.Add(item);
myTableRow.Cells.Add(myTableCell);
}
Table2.Rows.Add(myTableRow);
Page.Controls.Add(Table2);
}
解决方法
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