如何限制cakephp中的分页符

问题描述

| 如何限制cakePHP中的分页？ 假设我有400条记录。 我只需要从25条记录到75条记录中获得25条记录 并且每页需要显示5条记录。 我该如何做到分页？ 样例代码：

        $this->paginate = array(
                \'contain\'=>array(\'User\'),\'recursive\' => 2,\'order\' => array(\'Profile.winning\' => \'DESC\'),\'limit\' =>5

            );

    

解决方法

        您可以设置分页条件。

function listRecords()
  {
  $this->paginate = array(
    \'conditions\' => array(\'Model.id >=\' => 50,\'Model.id <=\' => 75),\'limit\' => 5
    );
  $this->paginate(\'Model\');
  );

编辑： 来自这里的解决方案：

$this->paginate = array(
  \'limit\' => 20,\'totallimit\' => 1000
  );

然后在模型中：

public function paginateCount($conditions = null,$recursive = 0,$extra = array())
  {
  if( isset($extra[\'totallimit\']) ) return $extra[\'totallimit\'];
  }

    ,        参考以下版本的改进版本：http://www.mainelydesign.com/blog/view/best-paginatecount-cakephp-with-group-by-support 这将返回较小的正确总数。

public function paginateCount($conditions = null,$extra = array()) 
    {
        $conditions = compact(\'conditions\');
        if ($recursive != $this->recursive) {
            $conditions[\'recursive\'] = $recursive;
        }
        unset( $extra[\'contain\'] );
        $count = $this->find(\'count\',array_merge($conditions,$extra));

        if (isset($extra[\'group\'])) {
            $count = $this->getAffectedRows();
        }

        if (isset($extra[\'totallimit\']) && $extra[\'totallimit\'] < $count) {
            return $extra[\'totallimit\'];
        }

        return $count;
    }

    ,        在CakePHP v2.x中使用ѭ5。

public $paginate = array(
    // other keys here.
    \'maxLimit\' => 10
);

在这里阅读更多有关它的信息。     ,        

$query = $this->User->find(\'all\',[
    \'recursive\' => 2,\'order\' => array(\'Profile.winning\' => \'DESC\'),\'limit\' => 25,\'offset\' => 50
]);
$this->paginate = array(
    $query,\'limit\' => 5
);