问题描述
|
根据以下2个表格,仅显示产品不离线时的活动时间。请记住,这只是一小部分数据。活动表中将有多个产品,离线表中将有多个时间戳。
目标是在产品在线时输出。因此,鉴于以下数据,我需要一个查询,该查询将返回:第3、6、7行-这些是产品在线时的时间戳记。
MysqL> select * from activity;
+------------+---------------------+
| product_id | activity_date |
+------------+---------------------+
| 1 | 2011-04-13 12:00:00 |
| 1 | 2011-04-13 01:00:00 |
| 1 | 2011-04-13 02:00:00 |
| 1 | 2011-04-13 03:00:00 |
| 1 | 2011-04-13 04:00:00 |
| 1 | 2011-04-13 05:00:00 |
| 1 | 2011-04-13 06:00:00 |
+------------+---------------------+
7 rows in set (0.01 sec)
MysqL> select * from offline
+------------+---------------------+---------------------+
| product_id | offline_start | offline_end |
+------------+---------------------+---------------------+
| 1 | 2011-04-13 12:00:00 | 2011-04-13 01:00:00 |
| 1 | 2011-04-13 03:00:00 | 2011-04-13 04:00:00 |
+------------+---------------------+---------------------+
2 rows in set (0.01 sec)
解决方法
create table activity
(
product_id int,activity_date datetime
);
create table [offline]
(
product_id int,offline_start datetime,offline_end datetime
);
insert into activity(product_id,activity_date)
values (1,\'2011-04-13 12:00:00 AM\'),(1,\'2011-04-13 01:00:00 AM\'),\'2011-04-13 02:00:00 AM\'),\'2011-04-13 03:00:00 AM\'),\'2011-04-13 04:00:00 AM\'),\'2011-04-13 05:00:00 AM\'),\'2011-04-13 06:00:00 AM\');
insert into [offline](product_id,offline_start,offline_end)
values (1,\'2011-04-13 12:00:00 AM\',\'2011-04-13 03:00:00 AM\',\'2011-04-13 04:00:00 AM\');
select a.*
from activity a
left join offline o
on a.product_id = o.product_id
and a.activity_date between o.offline_start and o.offline_end
where o.product_id IS NULL
在家中没有用于测试的mysql服务器设置,但如果AM不起作用,则12 AM为00:00:00,因此活动表上的第一个条目应为
1,\'2011-04-13 00:00:00\'
离线表的第一个条目应该是
1,\'2011-04-13 00:00:00\',\'2011-04-13 01:00:00\'
在我的sql服务器上测试了它,这是输出:
product_id activity_date
1 2011-04-13 02:00:00.000
1 2011-04-13 05:00:00.000
1 2011-04-13 06:00:00.000