问题描述
||
我将如何构造一个查询,将某个百分比以下的任何内容归类为“其他”?
例如:
Select Country,(COUNT(Country)*100 / (Select COUNT(*) From Logs)) as Perc
FROM Logs
Group by Country
HAVING (COUNT(Country)*100 / (Select COUNT(*) From Logs)) > 5
ORDER BY Perc DESC
我如何添加一行“ Other”,使所有内容的总和小于6%?
解决方法
另一种方法
;WITH Logs(Country) AS
(
SELECT TOP 10 \'UK\' FROM sys.objects UNION ALL
SELECT TOP 10 \'US\' FROM sys.objects UNION ALL
SELECT TOP 1 \'Timbuktu\' FROM sys.objects
),GroupedLogs AS
(
SELECT Country,(COUNT(Country) * 100.0 / (SELECT COUNT(*) FROM Logs)) AS Perc
FROM Logs
GROUP BY Country
)
SELECT CASE WHEN Perc<6 THEN \'Other\' ELSE Country END AS Country,SUM(Perc) AS Perc
FROM GroupedLogs
GROUP BY CASE WHEN Perc<6 THEN \'Other\' ELSE Country END
,我认为您需要一个UNION。未经测试,但类似:
SELECT * FROM
(
Select
Country,(COUNT(Country)*100 / (Select COUNT(*) From Logs)) as Perc
FROM
Logs
Group by
Country
HAVING
(COUNT(Country)*100 / (Select COUNT(*) From Logs)) >= 6
UNION
Select
\'Other\' as Country,(COUNT(Country)*100 / (Select COUNT(*) From Logs)) as Perc
FROM
Logs
HAVING
(COUNT(Country)*100 / (Select COUNT(*) From Logs)) < 6
)
ORDER BY
Perc DESC
,或尝试以下方法。此处的百分比是按CTE计算的:
DECLARE @countries TABLE (name varchar(16),hit INT);
INSERT INTO @countries
VALUES
(\'UK\',1),(\'UK\',(\'FRA\',(\'USA\',(\'MEX\',1);
WITH MY_PERCENTAGES AS
(
SELECT name,CAST(count(*) AS NUMERIC(5,2))
/
CAST(SUM(count(*)) OVER() AS NUMERIC(5,2)) * 100.
AS percentage
FROM @countries
GROUP BY name
)
SELECT
name,SUM (percentage) AS percentages
FROM
(
SELECT
CASE
WHEN percentage <6 THEN
\'OTHER\'
ELSE
name
END AS name,percentage
FROM MY_PERCENTAGES
) TMP
GROUP BY name;