PHP Symfony 命令和代码组织

问题描述

我正在使用控制台命令 Symfony 进行 http 调用。

快速示例工作：

private void insertFixUp(Node x) {
Node u = TNULL;
    while (x.parent.color == 1){
        if(x.parent == x.parent.parent.right){
            u=x.parent.parent.left;
        if (u.color == 1){
            u.color =0;
            x.parent.color = 0;
            x.parent.parent.color = 1;
            x = x.parent.parent;
        }
        else {
            if(x == x.parent.left) {
            x = x.parent;
            rightRotate(x);
        }
            x.parent.color=0;
            x.parent.parent.color=1;
            leftRotate(x.parent.parent);
        }
    } else {
            u = x.parent.parent.right;

            if (u.color == 1){
                u.color =0;
                x.parent.color = 0;
                x.parent.parent.color = 1;
                x = x.parent.parent;
            }
            else {
                if(x == x.parent.right) {
                    x = x.parent;
                    leftRotate(x);
                }
                x.parent.color=0;
                x.parent.parent.color=1;
                leftRotate(x.parent.parent);
            }
        }
        if(x == root){
            break;
        }
  }
    root.color=0;

}

<?PHP
namespace \App\Command;
use Symfony\Component\Console\Command\Command;
class MainCommand extends Command {
public function __construct(
        CallApiService $api,TekConfiguration $parserConfig,LoggerInterface $logger,ParameterBagInterface $param
    ) {
        parent::__construct();
        $this->api = $api;
        $this->logger = $logger;
        $this->parserConfig = $parserConfig;
        $this->param = $param;
    }
}

<?PHP
namespace \App\Command;

class FistCommand extends MainCommand{
  protected static $defaultName = 'tek:foo:bar';
  protected function configure(): void
  {
     ...
  }
  protected function execute(InputInterface $input,OutputInterface $output)
  {
      ...
       $this->api->callFoo();
      ...
  }

}

为了更好地组织我的代码，我想在从 CallApiService 继承的其他类中外部化 callFoo（和 callBar、callAnother..）方法。 喜欢：

<?PHP
namespace App\Tek;

use Psr\Log\LoggerInterface;
use Symfony\Contracts\HttpClient\HttpClientInterface;

class CallApiService{
public function __construct(HttpClientInterface $tek_api,LoggerInterface $logger)
    {
        $this->client = $tek_api; //scoped cf. framework.yaml
        $this->logger = $logger;
        $this->path = $_ENV['API_URL'] . $_ENV['API_PATH'];
        ... other common conf ...
    }

private function get(){
  ** do call httpclient get **
  ** and return response **

}

private function post(){
  ** do call httpclient post **
  ** and return response **
}

public function callFoo(array $params): array
    {
        $this->uri = $this->path . '/operations?operation=foo';
        return $this->post($params);
    }

但我不明白如何通过依赖注入避免重新声明构造函数

解决方法

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