当我在 Streamlit 中更改选择框时重新运行脚本

问题描述

当我更改选择框选项时重新运行脚本，我知道每个操作的流光代码都从顶部运行，并且有 2 个解决方案（缓存和 SessionState）我测试缓存它不起作用，而对于 SessionState 我不知道如何实施它

这是代码

import streamlit as st
col1,col2,col3 = st.beta_columns(3)
if col1.button("CARTE"):
    st.write("Hello")
    sel_Map = st.selectBox("Choose Map type :",options=['Hello1','Hello2'],index=1)
    if sel_Map == 'ChoroplethMap':
        st.write("Hello World! 1")

    elif sel_Map == 'ChoroplethMapBox':
        st.write("Hello World! 2")

if col2.button("TABLEAU"):
    st.write("Hello World! 3")

if col3.button("SYNTHÈSE"):
    st.write("Hello World! 4")

解决方法

我想出了如何使用 SessionState 所以结果很好，这是解决方案

import streamlit as st
from src.pages.sessionState import SessionState


session_state = SessionState.get(col1=False,col2=False,col3=False)

col1,col2,col3 = st.beta_columns(3)

col1_one = col1.button("CARTE",key="1")
col2_one = col2.button("TABLEAU",key="2")
col3_one = col3.button("SYNTHÈSE",key="3")

if col1_one or session_state.col1:
    session_state.col1 = True
    session_state.col2 = False
    session_state.col3 = False
    sel_Map = st.selectbox("Choose Map type :",options=['Hello1','Hello2'],index=1)
    if sel_Map == 'Hello1':
        st.write("Hello world! 1")
    elif sel_Map == 'Hello2':
        st.write("Hello world! 2")

if col2_one or session_state.col2:
    session_state.col1 = False
    session_state.col2 = True
    session_state.col3 = False
    st.write("Hello world! 3")

if col3_one or session_state.col3:
    session_state.col1 = False
    session_state.col2 = False
    session_state.col3 = True
    st.write("Hello world! 4")