如何在Processing中将数组数据与frameCount结合

问题描述

我试图让带圆圈的物体随着时间的推移出现——每个都是独立的——并在 30 帧后将它们的位置更改为随机选择的新位置。现在 - 我只能让他们在 30 帧后改变他们的位置,但一次全部......我花了一段时间以他们改变所有 30 帧的方式组合它们,现在我想解开它们。那是如何实现的?顺便说一句——“数字数组”一开始给出了零值的 6 倍,可能是因为它连接到循环?有没有办法解决这个问题?

这里可以看到主要代码

Circle[] circles = new Circle[6];

color c1 = color(255,255,255);
color c2 = color(0,255);
color c3 = color(255,255);
color[] colors = { c1,c2,c3 };

int[] numbers = new int[6];

int index;
float rX;
float rY;

void setup () {
  size(540,960);
  randomizePositions();
  
  index = 5;
  numbers[0] = 5;
  numbers[1] = 10;
  numbers[2] = 15;
  numbers[3] = 20;
  numbers[4] = 25;
  numbers[5] = 30;
}

void randomizePositions() {
  
  for (int i = 0; i <circles.length; i++) {
    rX = random(width);
    rY = random(height);
    index = int(random(numbers.length));
    circles[i] = new Circle(rX,rY,colors[int(random(0,colors.length))],numbers[index]);
  }
}

void draw() {
  background(#c1c1c1);
  for (int i = 0; i < circles.length; i++) {
    circles[i].display();
  }
  if (frameCount % 30 == 0) {
    randomizePositions();
  }
}

这是对象:

class Circle {

  int size;
  int number;
  float x;
  float y;
  color col;

  Circle(float tempX,float tempY,color tempC,int tempNumber) {
    size = 20;
    x = tempX;
    y = tempY;
    col = tempC;
    number = tempNumber;
  }

  void display() {
    fill(col);
    nostroke();
    ellipse(x,y,size/2.5,size/2.5);
    for (int i = 0; i < number; i++) {
      noFill();
      stroke(col);
      strokeWeight(size/2.5);
      ellipse(x,i*size,i*size);
    }
  }
}

感谢您的任何帮助或提示

解决方法

您可以从随机位置使用相同的逻辑,但在 for 循环之外:

tt100123,writer 
tt100123,writer,play
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如果您想避免每次在可重用函数中移动构造函数功能时都创建一个新对象:

void randomizePosition() {
  int randomCircleIndex = int(random(circles.length));
  int randomColorIndex = int(random(colors.length));
  int randomNumerIndex = int(random(numbers.length));
  rX = random(width);
  rY = random(height);
  circles[randomCircleIndex] = new Circle(rX,rY,colors[randomColorIndex],numbers[randomNumerIndex]);
}

此外,如果您想一次重置一个圆但顺序(不是从数组中随机选择一个),您需要使用一个单独的整数来计算当前选定的圆索引,以便它可以递增:

Circle[] circles = new Circle[6];

color c1 = color(255,255,255);
color c2 = color(0,255);
color c3 = color(255,255);
color[] colors = { c1,c2,c3 };

int[] numbers = new int[6];

int index;
float rX;
float rY;

void setup () {
  size(540,960);
  randomizePositions();

  index = 5;
  numbers[0] = 5;
  numbers[1] = 10;
  numbers[2] = 15;
  numbers[3] = 20;
  numbers[4] = 25;
  numbers[5] = 30;
}

void randomizePositions() {

  for (int i = 0; i <circles.length; i++) {
    rX = random(width);
    rY = random(height);
    index = int(random(numbers.length));
    circles[i] = new Circle(rX,colors[int(random(0,colors.length))],numbers[index]);
  }
}

void randomizePosition() {
  int randomCircleIndex = int(random(circles.length));
  int randomColorIndex = int(random(colors.length));
  int randomNumerIndex = int(random(numbers.length));
  rX = random(width);
  rY = random(height);
  circles[randomCircleIndex].reset(rX,numbers[randomNumerIndex]);
}

void draw() {
  background(#c1c1c1);
  for (int i = 0; i < circles.length; i++) {
    circles[i].display();
  }
  if (frameCount % 30 == 0) {
    randomizePosition();
  }
}

class Circle {

  int size;
  int number;
  float x;
  float y;
  color col;
  
  Circle(float tempX,float tempY,color tempC,int tempNumber) {
    reset(tempX,tempY,tempC,tempNumber);
  }
  
  void reset(float tempX,int tempNumber){
    size = 20;
    x = tempX;
    y = tempY;
    col = tempC;
    number = tempNumber;
  }

  void display() {
    fill(col);
    noStroke();
    ellipse(x,y,size/2.5,size/2.5);
    for (int i = 0; i < number; i++) {
      noFill();
      stroke(col);
      strokeWeight(size/2.5);
      ellipse(x,i*size,i*size);
    }
  }
  
  
}