问题描述
版本: Python:3.9 | Pymodbus:2.5.1
Pymodbus 特定: 服务器:rtu - 同步/异步 | 客户端:rtu - 同步/异步
说明:
我想在图形用户界面上点击一个按钮后启动pymodbus的SerialServer。 但是单击按钮后,Gui 停止了,我必须停止我的程序。 Gui 打开时无法运行 SerialServer。
from pymodbus.version import version
from pymodbus.server.asynchronous import StartSerialServer
#from pymodbus.server.sync import StartSerialServer
from pymodbus.device import Modbusdeviceidentification
from pymodbus.datastore import ModbussparseDataBlock
from pymodbus.datastore import ModbusSlaveContext,ModbusServerContext
from pymodbus.transaction import ModbusRtuFramer
import sys
from qtpy import QtWidgets
app = QtWidgets.QApplication(sys.argv)
def modbus_send():
class CustomDataBlock(ModbussparseDataBlock):
def setValues(self,address,value):
super(CustomDataBlock,self).setValues(0,10)
super(CustomDataBlock,self).setValues(1,11)
super(CustomDataBlock,self).setValues(2,12)
#print("wrote {} to {}".format(value,address))
block = CustomDataBlock({0: [0] * 100})
store = ModbusSlaveContext(hr=block)
context = ModbusServerContext(slaves=store)
identity = Modbusdeviceidentification()
identity.vendorName = 'pymodbus'
identity.ProductCode = 'PM'
identity.vendorUrl = 'http://github.com/riptideio/pymodbus/'
identity.ProductName = 'pymodbus Server'
identity.ModelName = 'pymodbus Server'
identity.MajorMinorRevision = version.short()
StartSerialServer(context,framer=ModbusRtuFramer,identity=identity,port='COM7',timeout=0.05,baudrate=19200)
window = QtWidgets.QMainWindow()
window.setwindowTitle("StartSerialServer")
window.setGeometry(500,500,50)
button = QtWidgets.QPushButton(window)
button.setText("Start")
button.show()
button.clicked.connect(modbus_send())
window.show()
sys.exit(app.exec_())
解决方法
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