问题描述
我必须从表中选择两种类型的结果集并将它们合并到单个 json 数组中 喜欢
select col1,col2,col3 from table 1 order by col3 where col1< 2
union all
select col1,col3 from table 1 order by col1 where colo = 3
我认为这是由于 order by 导致的语法错误。
我需要在 json 数组中返回它,所以我正在尝试这样
SELECT ( SELECT json_agg(row)
FROM (
select col1,col3 from table 1 order by col3 where col1< 2 ) row)
UNION ALL
SELECT (SELECT json_agg(row)
FROM (
select col1,col3 from table 1 order by col1 where colo = 3
) row)
它正在停用两个 json 数组,即很明显,我怎样才能在单个数组中做到这一点
谢谢,
解决方法
在 UNION 之后进行聚合:
select json_agg(t)
from (
(select col1,col2,col3 from table1 order by col3 where col1< 2)
union all
(select col1,col3 from table1 order by col1 where colo = 3)
) t