MySQL如何美化JSON_ARRAYAGG/JSON_OBJECT的SQL查询？

问题描述

假设我在 salary_table 中有一些示例数据，如下所示：

    id     name        year            avg_salary
   --------------------------------------------
1   1    alice        2019         17410.407500
2   2    elsa         2020        14562.580000
3   3    edward       2019         15234.580000
4   4    anna         2021         15934.580000
.....
99  999    mike         2019        7410.407500
100 1000    mike         2020       17410.407500

我尝试使用下面的sql可以得到我需要的结果，

SELECT
concat(id,'/',name),JSON_ARRAYAGG(
                JSON_OBJECT(
                        "year",year,"avg_salary",avg_salary
                )
        ) as detail
FROM salary_table
GROUP BY 1
ORDER BY 1 ASC

但是上面的结果很丑，

id/name   detail
----------------------
1/alice      [{"year": 2019,"avg_salary": 17410.407500},{"year": 2020,"avg_salary": 21331.052857},{"year": 2021,"avg_salary": 19101.316667}]
2/elsa       [{"year": 2020,"avg_salary": 14562.580000}]
3/edward     [{"year": 2019,"avg_salary": 15234.580000}]
4/anna       [{"year": 2021,"avg_salary": 15934.580000}]
5/ann        [{"year": 2020,"avg_salary": 11331.052857},"avg_salary": 9101.316667}]
6/cathy      [{"year": 2018,"avg_salary": 7410.407500},{"year": 2019,"avg_salary": 9101.316667}]

我的完美输出如下，实际上，我的结果中不需要 JSON_ARRAYAGG：

-----------------
id  name 2018_avg_salary   2019_avg_salary   2020_avg_salary   2021_avg_salary
1  alice  17410.4075       21331.05286       21331.05286   21331.05286
2  elsa   17411.4075       21332.05286       21332.05286   21332.05286

如何美化MysqL中JSON_ARRAYAGG/JSON_OBJECT的SQL查询？

解决方法

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