问题描述
我保留了自定义维度(用户 ID 和商家)中的联接值。我还想添加交易。我能否就如何将其添加到此查询中获得一些建议?还是我必须完全改变结构?这是我尝试的方式,但我收到一个语法错误,提示它需要在 FROM 语句所在的位置输入结束输入。
merchants.merchant_Id,otherMerchants.merchant_id AS otherMerchants,merchants.market AS market,COUNT (merchants.transactions) AS transactions,COUNT(disTINCT merchants.userId) users
FROM(
SELECT
#här hämtar vi alla userIds och merchantIds
(SELECT VALUE FROM UNnesT(customDimensions) WHERE INDEX = 3) userid,(SELECT VALUE FROM UNnesT(customDimensions) WHERE INDEX = 4) merchant_Id,(SELECT VALUE FROM UNnesT (customDimensions) WHERE INDEX = 8) market,hits.transaction.transactionId) as transactions
FROM `qliro-66ee8.128389777.ga_sessions_20210628`
UNnesT (hits) AS hits
) merchants
LEFT JOIN
(
SELECT
#här hämtar vi alla userIds och merchantIds igen för att kunna nyckla ihop det
(SELECT VALUE FROM UNnesT(customDimensions) WHERE INDEX = 3) userid,(SELECT VALUE FROM UNnesT(customDimensions) WHERE INDEX = 4) merchant_id,hits.transaction.transactionId) as transactions
FROM `qliro-66ee8.128389777.ga_sessions_20210628`
UNnesT (hits) AS hits
) otherMerchants
#nycklar på att det är samma user samt inte samma merchant för att inte få dubbelräkning
#nycklar på att det är samma user samt inte samma merchant för att inte få dubbelräkning
ON merchants.userId = otherMerchants.userid
AND merchants.merchant_Id != otherMerchants.merchant_id
AND merchants.transactions = otherMerchants.transactions
AND merchants.market = otherMerchants.market
GROUP BY 1,2,3
解决方法
我觉得你很亲近!你应该做这样的事情
SELECT
merchants.merchant_Id,otherMerchants.merchant_id AS otherMerchants,merchants.market AS market,SUM(merchants.transactions) AS transactions,COUNT(DISTINCT merchants.userId) users
FROM(
SELECT
(SELECT VALUE FROM UNNEST(t1.customDimensions) WHERE INDEX = 3) userid,(SELECT VALUE FROM UNNEST(t1.customDimensions) WHERE INDEX = 4) merchant_Id,(SELECT VALUE FROM UNNEST (t1.customDimensions) WHERE INDEX = 8) market,count(distinct hits.transaction.transactionId) as transactions
FROM `qliro-66ee8.128389777.ga_sessions_20210628` t1,UNNEST (hits) AS hits
GROUP BY 1,2,3
) merchants
LEFT JOIN
(
SELECT
#här hämtar vi alla userIds och merchantIds igen för att kunna nyckla ihop det
(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 3) userid,(SELECT VALUE FROM UNNEST(customDimensions) WHERE INDEX = 4) merchant_id,(SELECT VALUE FROM UNNEST (customDimensions) WHERE INDEX = 8) market
FROM `qliro-66ee8.128389777.ga_sessions_20210628`
) otherMerchants
ON merchants.userId = otherMerchants.userid
AND merchants.merchant_Id != otherMerchants.merchant_id
AND merchants.market = otherMerchants.market
GROUP BY 1,3
编辑:查询中缺少 GROUP BY 语句