问题描述
我正在构建一个应用程序并希望拥有主要、次要和三次按钮,我不想创建 3 个单独的组件,这些组件是相同的但具有不同的样式组件,因此我想有条件地显示正确的标签,例如下面的代码,但我收到错误 JSX 元素类型“ButtonStyles”没有任何构造或调用签名。我究竟做错了什么?谢谢
import React from "react";
import styled from "styled-components";
const PrimaryStyles = styled.button`
width: 26rem;
height: 5rem;
background-image: ${({ theme }) => theme.gradients.ry};
border: none;
border-radius: 4px;
color: ${({ theme }) => theme.black};
font-size: 2rem;
Box-shadow: 3px 3px 30px ${({ theme }) => theme.red + "70"};
cursor: pointer;
padding: 0 1rem;
`;
const SecondaryStyles = styled.button``;
const TertiaryStyles = styled.button`
border: none;
background: none;
color: ${({ theme }) => theme.grey};
`;
interface IProps {
type: "button" | "reset" | "submit";
children: React.ReactNode;
onClick: React.MouseEventHandler<HTMLButtonElement>;
primary?: boolean;
secondary?: boolean;
tertiary?: boolean;
}
export const Button: React.FC<IProps> = ({
children,onClick,type,primary = true,secondary,tertiary,}) => {
const ButtonStyles = primary
? PrimaryStyles
: secondary
? SecondaryStyles
: tertiary
? TertiaryStyles
: null;
return (
<ButtonStyles type={type} onClick={onClick}>
{children}
</ButtonStyles>
);
};
解决方法
这是因为这个逻辑:
const ButtonStyles = primary
? PrimaryStyles
: secondary
? SecondaryStyles
: tertiary
? TertiaryStyles
: null;
如果不是 primary
、secondary
或 tertiary
,它将是 null
。因此,您的代码会将 ButtonStyles
设置为 NULL
,然后您不能这样做:
return (
<ButtonStyles type={type} onClick={onClick}>
{children}
</ButtonStyles>
);
对此的解决方案是删除 NULL
选项,例如:
const ButtonStyles = primary
? PrimaryStyles
: secondary
? SecondaryStyles
: TertiaryStyles;
另一种避免三元条件运算符的方法是:
- 创建一个包含 3 个样式选项的对象:
interface IButtonStyles {
[key: string]: StyledComponent<"button",any,{},never>;
}
const buttonStyleTypes: IButtonStyles = {
primary: PrimaryStyles,secondary: SecondaryStyles,tertiary: TertiaryStyles,};
- 将您的 IProps 更改为类似的内容:
interface IProps {
type: "button" | "reset" | "submit";
children: React.ReactNode;
onClick: React.MouseEventHandler<HTMLButtonElement>;
styleType?: string;
}
- 按钮组件:
const Button: React.FC<IProps> = ({
children,type,styleType = "primary",}) => {
const ButtonStyles = buttonStyleTypes[styleType];
return <ButtonStyles type={type}>{children}</ButtonStyles>;
};
- 最后,您可以像这样创建按钮:
<Button type={"button"}>primary</Button>
<Button type={"button"} styleType='secondary'>secondary</Button>
<Button type={"button"} styleType='tertiary'>tertiary</Button>