python电报机器人商店聊天ID

问题描述

我想知道如何存储/读出用户聊天 ID 以便以后向他们发送消息。

例如，用户正在添加我的电报机器人并向他发送消息。 稍后在我的程序中的某个时候，当发生特定情况时，我想向特定用户发送消息。

举个简单的例子，我有这个代码：

a=1
b=2

if a > b:
     # at this point python should send a message to a user via telegram privat chat

else:
    # send a different message

我知道如何处理对用户在电报聊天中发送的命令的响应，但不知道如何在不先收到命令的情况下向用户发送消息。我认为因此我需要有一种方法来首先存储用户聊天 ID，以便稍后在发送消息时引用该 ID。

重点是我想稍后将我的程序编译为 .exe 并将其发送给一些朋友，它应该也适用于他们。

解决方法

您可以简单地将 id 添加到列表中，而无需任何第三方包

import telebot

TOKEN = ""
bot = telebot.TeleBot(TOKEN)

admin = # your chat id
users = []

@bot.message_handler(commands=['start'])
def start_message(msg):
    bot.send_message(msg.chat.id,'Welcome!')
    if msg.chat.id not in users: # if the id isn't already in the users list
        users.append(msg.chat.id)

@bot.message_handler(commands=['send_at_all']) # A way to use the list
def sendAtAll(msg):
    if msg.chat.id == admin: # only if YOU start the command the message will be sent
        for id in users: # for every user that has start the bot
            bot.send_message(id,"I'm sending this message at all the users")

# If an user wants to stop the notifications...

@bot.message_handler(commands=['unsubscribe'])
def sendAtAll(msg):
    del users[msg.chat.id]
    bot.send_message(msg.chat.id,"If you want to receive the notification click /start")


# Every time you are going to restart the bot polling the content of the users list will be deleated so...

@bot.message_handler(commands=['save_user_list'])
def sendAtAll(msg):
    if msg.chat.id == admin:
        bot.send_message(admin,users) 
# the list will be sent to your telegram chat,when you activate the bot you can add the list manually

bot.polling()

您还可以创建一个类并将每个聊天 ID 保存为一个对象

import telebot
from random import choice

TOKEN = ''
bot = telebot.TeleBot(TOKEN)

admin = # your chat id
users = []

class Userbot: # The class User is already in the pyTelegramBotAPI
    def __init__(self,msg):
        self.id = msg.chat.id
        self.username = '@' + msg.from_user.username

    def contestWinner(self):
        text = f'Hi {self.username},you have win!!!'
        bot.send_message(self.id,text)



@bot.message_handler(commands=['start'])
def start(msg):
    bot.send_message(msg.chat.id,'Welcome!')
    for el in users: 
        if msg.chat.id not in el.id:
            users.append(Userbot(msg))
# you can't type 'if msg.chat.id not in users.id' because only the object inside the list can use the method id


@bot.message_handler(commands=['extract']) # another way to use the list
def extract(msg):
    if msg.chat.id == admin:
        winner = choice(users)
        winner.contestWinner()


@bot.message_handler(commands=['unsubscribe'])
def sendAtAll(msg):
    for el in users: 
        if msg.chat.id == el.id:
            del users[el]
    # only if the user inside the object is the same as the user that has sent the message the object will be deleated
    bot.send_message(msg.chat.id,"If you want to receive the notification click /start")


@bot.message_handler(commands=['save_user_list'])
def sendAtAll(msg):
    if msg.chat.id == admin:
        bot.send_message(admin,users)

bot.polling()

为我糟糕的英语道歉

,

很简单，只需使用一个简单的数据库。 在我看来，MongoDB 是最好的选择。 在其上创建一个帐户并关注this tutorial。

首先获取user_id

userid1 = str(update.message.chat_id)

然后存入数据库

    import pymongo
    from pymongo import MongoClient

    cluster = MongoClient("mongodb+srv://<user>:<password>@cluster0.uubct.mongodb.net/users?retryWrites=true&w=majority")
    db = cluster["users"]
    collection = db["users"]

    results = collection.find({"_id": int(userid1)})

    if results.count() == 0:
        print("post")
        
        post = {"_id": int(userid1)}
        collection.insert_one(post)

    else:
        print("User already in the database!")

要获得它，您需要使用 find() 方法。

results = collection.find()

    for result in results:
        var1 = (result["_id"])

        print(var1)
        
        context.bot.send_message(chat_id=prova,text = "Hi")