问题描述
我正在尝试在 Lambda 函数中编写 Python 代码,该代码将在警报触发时启动已停止的工作区。响应类型为 dict。
import json
import boto3
client = boto3.client('workspaces')
def lambda_handler(event,context):
response = client.describe_workspaces(
DirectoryId='d-966714f114'
)
#print(response)
print("hello")
for i in response['Workspaces']:
if(i['State']== 'STOPPED'):
print(i['WorkspaceId'])
client.start_workspaces(i['WorkspaceId'])
{
"errorMessage": "start_workspaces() only accepts keyword arguments.","errorType": "TypeError","stackTrace": [
" File \"/var/task/lambda_function.py\",line 21,in lambda_handler\n client.start_workspaces(i)\n"," File \"/var/runtime/botocore/client.py\",line 354,in _api_call\n raise TypeError(\n"
]
}
解决方法
如果您查看调用的 here,它说它需要关键字 StartWorkspaceRequests
,它本身就是一个字典列表:
{
'WorkspaceId': 'string'
},
调用不接受参数(只是传递一个没有相应关键字的值)。您需要调整您的调用以符合 boto3 预期的格式。
import json
import boto3
client = boto3.client('workspaces')
def lambda_handler(event,context):
response = client.describe_workspaces(
DirectoryId='d-966714f114'
)
workspaces_to_start = []
for i in response['Workspaces']:
if(i['State']== 'STOPPED'):
workspaces_to_start.append({'WorkspaceId': i['WorkspaceId']})
if workspaces_to_start:
client.start_workspaces(StartWorkspaceRequests=workspaces_to_start)