问题描述
更新
我能够更接近我想要实现的目标。还需要工作。我尝试使用圆角矩形作为蒙版,但看起来不太好。任何建议将不胜感激。
SELECT * FROM (select table_1.id,table_1.fname,table_1.lname,table2.room,CASE
WHEN id_rank = 1 THEN contact1
WHEN id_rank = 2 THEN contact2
WHEN id_rank = 3 THEN contact3
END as contact
FROM
(
select
table_1.id,table_3.contact1,table3.contact2,table_3.contact3,dense_rank() over ( partition by table3.id order by table_1.id asc )
as "id_order"
FROM
table_3 left join
table_1 on table_3.cid = table_1.id
left join table_2
on table_1.room = table_2.id
where
table_1.location = 1
and
table_1.room in (1,2,3,4,5,6,7,8,9,10,11)
) as sub_query
)
as main_query
WHERE contact is NOT NULL;
年长
我正在尝试创建一个简单的仪表,例如 watchOS 中的线性仪表。我遇到的问题是找出覆盖当前值的正确方法。我想看到的结果如下。我相信有更好的方法。
结果
我的看起来非常糟糕
GeometryReader { geometry in
RoundedRectangle(cornerRadius: 7.5,style: .circular)
.fill(LinearGradient(gradient: Gradient(colors: [Color.green,Color.yellow,Color.orange,Color.red,Color.purple]),startPoint: .bottom,endPoint: .top))
.frame(width: geometry.size.width,height: geometry.size.height,alignment: .bottomLeading)
.overlay(Color.black.opacity(0.35).cornerRadius(7.5))
RoundedRectangle(cornerRadius: 7.5,alignment: .bottomLeading)
.mask(
vstack {
Spacer()
Rectangle()
// Adjust value 1 to needs
.frame(width: geometry.size.width,height:geometry.size.height * (CGFloat(1) / CGFloat(11)),alignment: .bottom)
})
}
.frame(width: 15,height: .infinity)
.padding(.all,10)