如何使用 Python 对字数进行排序？

问题描述

我正在使用此代码计算文本文件中相同的单词。

filename = input("Enter name of input file: ")
file = open(filename,"r",encoding="utf8")
wordCounter = {}
with open(filename,'r',encoding="utf8") as fh:
  for line in fh:
    # Replacing punctuation characters. Making the string to lower.
    # The split will spit the line into a list.
    word_list = line.replace(',','').replace('\'','').replace('.','').replace("'",'').replace('"','').replace('#','').replace('!','').replace('^','').replace('$','').replace('+','').replace('%','').replace('&','').replace('/','').replace('{','').replace('}','').replace('[','').replace(']','').replace('(','').replace(')','').replace('=','').replace('*','').replace('?','').lower().split()
    for word in word_list:
      # Adding  the word into the wordCounter dictionary.
      if word not in wordCounter:
        wordCounter[word] = 1
      else:
        # if the word is already in the dictionary update its count.
        wordCounter[word] = wordCounter[word] + 1

print('{:15}{:3}'.format('Word','Count'))
print('-' * 18)
# printing the words and its occurrence.
for  word,occurance  in wordCounter.items():
  print(word,occurance)

我需要它们按顺序排列，从大到小作为输出。例如：

词 1：25

词 2：12

词 3：5 . . .

我还需要将输入作为“.txt”文件获取。如果用户写了任何不同的东西，程序必须得到一个错误“写一个有效的文件名”。

如何排序输出并同时生成错误代码？

解决方法

为了按顺序打印，您可以在打印之前按这样的出现对它们进行排序：

for  word,occurance  in sorted(wordCounter.items(),key=lambda x: x[1],reverse=True):
  print(word,occurance) 

为了以您想要的方式检查文件是否有效，您可以考虑使用：

import os

path1 = "path/to/file1.txt"
path2 = "path/to/file2.png"

if not path1.lower().endswith('.txt'):
    print("Write a valid file name")

if not os.path.exists(path1):
    print("File does not exists!")

,

你可以试试：

if ( filename[-4:0] != '.txt'):
    print('Please input a valid file name')

并重复输入命令...