问题描述
我想在 Athena 中解析 JSON 列,但我在某一列中遇到了问题。该列包含一个转义字符。不知道有没有这个问题。我想联系消息。您可以在返回下看到以下示例数据和消息。谢谢
Sample Code
CAST(json_extract_scalar(callparameters,'$return.Message') AS VARCHAR) AS Message
这是 JSON。
{"inputs":{"usagespecid":"null","playsessionid":"null","satellitetypecd":"\"ERU\"","channelcontentid":"231"},"return":"{\"Message\":\"Do not person you have called \"}"} {"date":"2021-07-26","epoch":"1627"} {"userpartyid":"23","userloginkey":"23","usercountrycode":"br","sessionkey":"23","client":{"name":"SMR","id":"1"},"usermainsatellitetype":"DS","userserviceaccountids":["23"],"usergeolocationid":"53","userpartyroleid":"76"}
解决方法
如果只取包含 return
的对象,则可以使用 json_parse
将 return
解析为 json,因为它包含编码字符串而不是 json 对象:
WITH dataset AS (
SELECT * FROM (VALUES
(JSON '{
"inputs":{
"usagespecid":"null","playsessionid":"null","satellitetypecd":"\"ERU\"","channelcontentid":"231"
},"return":"{\"Message\":\"Do not person you have called \"}"
}')
) AS t (json_string))
SELECT json_extract_scalar(json_parse(json_extract_scalar(json_string,'$.return')),'$.Message')
FROM dataset
输出:
_col0 |
---|
不要找你打电话的人 |